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3 years ago

WILL MARK BRAINLIEST

Mathematics

1 answer:

kherson [118]3 years ago

6 0

Answer

g(x) = x^3 − x^2 − 4x + 4

End behavior- Falls to the left rises to the right

y intercept-(0, 4)

Zeros- (1,-2,2)

g(x) = x^3 + 2x^2 − 9x − 18

End behavior- Falls to the left rises on the right

y intercept- (0,-18)

Zeros- (-2,-3,3)

g(x) = x^3 − 3x^2 − 4x + 12

End behavior-Falls to the left rises to the right

y intercept-(0,12)

Zeros- (3,-2,2)

g(x) = x^3 + 2x^2 − 25x − 50

End behavior- falls to the left rises to the right

y intercept(0,-50)

Zeros- (-2,-5,5)

g(x) = 2x^3 + 14x^2 − 2x − 14

End behavior- falls to the left rises to the right

y intercept-(0,-14)

Zeros- (-7,-1,1)

Step-by-step explanation:

~Plz tap the crown~

~ Thank you~

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Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi

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Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ $x=\frac{x_{1}+x_{2}}{2}$ and $y=\frac{y_{1}+y_{2}}{2}$

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is $x=\frac{-31+29}{2}=-1$

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is $y=\frac{8+-10}{2}=-1$

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed $\frac{2}{3}$ of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ $x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}$ and $y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}$

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is $x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11$

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is $x=\frac{(8)(1)+(-1)(2)}{2+1}=2$

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

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Answer:

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Step-by-step explanation:

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False its not always the actual dimensions

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ikadub [295]

The answer is D.

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2 years ago

Please help on one math question

kipiarov [429]

Hello from MrBillDoesMath!

Answer:

225

Discussion:

Sum ( 2n - 1) from n = 1 to 15

= Sum(2n) - Sum(1) from n = 1 to 15

= 2 Sum(n) - Sum(1) from n = 1 to 15

= 2* 15(15+1)/2 - (1 + 1 + .. + 1)

The first value comes from the fact that the sum of the first n integers is n(n+1)/2. The latter value sums 15 1's.

= 2 * 15 * 16/2 - 15 => 2/2 = 1

= 15*16 - 15 => 15*16 = 240

= 240 - 15

= 225

Thank you,

MrB

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