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kaheart [24]
3 years ago
7

Substance A has twice the specific heat capacity as substance B. If 1000 J of heat are added to 1.0 kg of each substance, compar

e the change in temperature of each substance.
Physics
1 answer:
Mrrafil [7]3 years ago
4 0
Substance A would have a delta T (change in temp) rise 1/2 the rise in substance B.

Q=mc x delta T

Q= heat energy in Joules
m= mass of substance heated or cooled
c= specific heat
ΔT is change in temp.

Solve for change in temp=. Q/mc

Specific heat and mass are not inversely proportional to heat energy input.

Putting into real world scenario of using water to heat a building.

Specific heat of water is 1.
It takes 1 btu to raise one pound of water 1 degF. at a base of 60 degF

Acetone specific heat is .51

So it takes half the amount of heat input to get a 100 degree ΔT, as compared to water.
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An object has an acceleration of 6.0 m/s/s. If the net force was doubled and the mass was one-third the original value, then the
alexandr402 [8]

Hahahahaha. Okay.

So basically , force is equal to mass into acceleration.

F=ma

so when F=ma , we get acceleration=6m/s/s

Force is doubled.

Mass is 1/3 times original.

2F=1/3ma

Now , we rearrange , and we get 6F=ma

So , now for 6 times the original force , we get 6 times the initial acceleration.

So new acceleration = 6*6= 36m/s/s

5 0
4 years ago
Question 7 (2 points)
Arlecino [84]

Answer:

Tire

Explanation:

3 0
3 years ago
Among all the electromagnetic waves (EM), which has the highest frequency? *
puteri [66]

first is gamma Ray's, last is d

8 0
3 years ago
In a double-slit experiment, the slits are illuminated by a monochromatic, coherent light source having a wavelength of 609 nm.
Ray Of Light [21]

Answer:

\Delta x = 3.65 \mu m

Explanation:

As we know that the sixth order maximum will have path difference given as

\Delta x = N\lambda

here we know that

N = order of maximum

\lambda = 609 nm

now we have

N = 6

so we know that

\Delta x = 6(609 nm)

\Delta x = 3.65 \mu m

6 0
3 years ago
A proton, traveling with a velocity of 3.7 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 5.4
Vikki [24]
The magnetic force (Lorentz force) experienced by the proton in the magnetic field is given by
F=qvBsin\theta=qvB
since \theta = 90^{\circ}, because the velocity v and the force F in this problem are perpendicular, and so also the angle \theta between the velocity and the magnetic field B should be 90^{\circ}.

Let's find the magnitude of the magnetic field; this is given by
B= \frac{F}{qv}= \frac{5.4\cdot 10^{-14}N}{1.6\cdot 10^{-19}C \cdot 3.7\cdot 10^6 m/s}=0.091 T

To understand the direction, let's use the right-hand rule:
-index finger: velocity
- middle finger: magnetic field
- thumb: force

Since the velocity (index) points east and the force (thumb) points south, then the magnetic field (middle finger) points downwards. So we write:
B = -0.091 T
8 0
4 years ago
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