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Complete question is: You pull your car into your driveway and stop. The drive shaft of your car engine, initially rotating at 2400 rpm,slows with a constant rotational acceleration of magnitude 30 rad/s². How long does it take for the drive shaft to stop turning?
Answer:
8.37 s
Explanation:
Initial rotational velocity, ω₀ = 2400 rpm = 2400 × 2π/60 = 251.2 rad/s
Final velocity, ω = 0
rotational deceleration, α =- 30 rad/s²
Use the first equation of rotational motion:
![t = \frac{\omega - \omega_o}{\alpha}](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7B%5Comega%20-%20%5Comega_o%7D%7B%5Calpha%7D)
Substitute the values:
![t = \frac{0 - 251.2}{-30}=8.37 s](https://tex.z-dn.net/?f=%20t%20%3D%20%5Cfrac%7B0%20-%20251.2%7D%7B-30%7D%3D8.37%20s)
Answer:
True.
Explanation:
If the sum of the external forces on an object is zero, then the sum of the external torques on it must also be zero.
The net external force and the net external torque acting on the object have to be zero for an object to be in mechanical equilibrium.
Hence, the given statement is true.
Answer:
63.36 kJ
Explanation:
Potential energy (PE) is the energy stored within an object, due to the object's position, arrangement or state.
Since the Boulder is now on a height , it has a potential energy
<em>Potential Energy = mass * gravitational acceleration * height</em>
(Assume the gravitational acceleration = 10ms⁻²)
![PE =m*g*h\\=264*10*24\\=63360 J\\=63.36 kJ](https://tex.z-dn.net/?f=PE%20%3Dm%2Ag%2Ah%5C%5C%3D264%2A10%2A24%5C%5C%3D63360%20J%5C%5C%3D63.36%20kJ)
Answer:
The answer is 100% A THE ANSWER IS A!!!!
Explanation:
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