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Misha Larkins [42]
3 years ago
14

Centripetal force is a centering force related to acceleration. The centripetal force when driving prevents which of the followi

ng from happening?
A. Semi-truck from taking too long to brake.

B. The tires from coming off their rims

C. The car from driving off the road on a curve

D. The car from turning the other way in ice
​
Physics
1 answer:
aivan3 [116]3 years ago
4 0

Answer:

C. The car from driving off the road on a curve

Explanation:

A centripetal force actually causes circular motion. This occurs when an object moves in a circular path or a circle,a force will definitely act on it.

For instance, a car travelling in a circular path must definitely experience this force acting on it, even when the car moves at a constant speed. If it does not exist the object will definitely spin off in a direction tangential to the circular path or curve.

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Answer:

Option B

The correct answer is 2

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3. You are flying 2586 miles from San Francisco to New York. An hour into the flight, you are 600
Citrus2011 [14]

Answer:

268.2 m/s (1dp)

Explanation:

600 miles = 965,606m (1mile = 1609.34m)

965606/60 = 16,0943.43 ..... (metres traveled every minute)

16,0943.43/60 = 268.2238 .....

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Which elements will bond ionically with barium such that the formula would be written as BaX2? A) Nitrogen, chlorine, and sodium
erma4kov [3.2K]

The answer would be:

B. Chlorine, iodine and Fluorine

Barium has 2 valence electrons. To satisfy the BaX₂ , this would mean that Barium will need to give one of each of its electrons. The elements that need 1 electron would be those that have 7 valence electrons to complete the octet. These elements would fall in group 7 or halogens. Chlorine, iodine and fluorine are all in Group 7, so this would be the best choice.

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If
mart [117]

Answer:  29.50 m

Explanation: In order to calculate the higher accelation to stop a train  without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:

f=μ*N the friction force is equal to coefficient of static friction  multiply the normal force (m*g).

f=m.a=μ*N= m*a= μ*m*g= m*a

then

a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2

With this value we can determine the short distance to stop the train

as follows:

x= vo*t- (a/2)* t^2

Vf=0= vo-a*t then t=vo/a

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