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Andreyy89
1 year ago
7

What is the average value expected for the independent-measures t statistic if the null hypothesis is true?

Physics
1 answer:
Bogdan [553]1 year ago
5 0

The average value for t- statistics is 0 if null hypothesis is true.

What is a t – statistics and null hypothesis ?

  • The t-statistic, which is used in statistics, measures how far a parameter's estimated value deviates from its hypothesized value relative to its standard error.
  • Through the Student's t-test, it is utilized in hypothesis testing. In a t-test, the t-statistic is used to decide whether to accept or reject the null hypothesis.
  • It is quite comparable to the z-score, but when the data is small or the standard deviation is unknown, the t-statistic is employed instead.
  • The default assumption, or null hypothesis, is that the quantity being measured is zero (null). The quantity to be assessed is often the difference between two circumstances.
  • Trying to determine, for instance, whether there is conclusive evidence that an impact has happened or that samples come from several batches

The t-test yields a t-value of 0 if the sample data precisely match the null hypothesis. The value of the t-value rises as the sample data diverge more and more from the null hypothesis.

To learn more about null hypothesis visit here:

brainly.com/question/25263462

#SPJ4

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A bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. The distance from the windowsill to the g
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The distance an object falls from rest through gravity is

                         D  =  (1/2) (g) (t²)

            Distance  =  (1/2 acceleration of gravity) x (square of the falling time)

We want to see how the time will be affected
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So I'm going to start by rearranging the equation
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                                                      D  =  (1/2) (g) (t²)

Multiply each side by  2 :         2 D  =            g    t² 

Divide each side by ' g ' :      2 D/g =                  t²

Square root each side:        t = √ (2D/g)


Looking at the equation now, we can see what happens
to ' t ' when only ' g ' changes: 

-- ' g ' is in the denominator; so bigger 'g' ==> shorter 't'
                                             and smaller 'g' ==> longer 't' .

-- They don't change by the same factor, because  1/g  is inside
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Gravity on the surface of the moon is roughly  1/6  the value
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4 0
3 years ago
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Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

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Learn more about radial velocity here:

<u>brainly.com/question/13117597</u>

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