0.11 moles of Aluminium chloride
<u>Explanation:</u>
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Given:
2Al + 3Cl₂ → 2AlCl₃
According to the balanced equation:
2 moles pf Aluminium form 2 moles of Aluminium chloride.
So, 1 mole of Al will form 1 mole of Aluminium chloride.
0.11 mole of Al is present.
So, 0.11 mol of Al will form 0.11 mol of Aluminium chloride.
The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
It will generate water and kind of salt ,such as:
HCl+NaOH==>NaCl+H2O
Answer:
Dip one end of the blue litmus paper into the solution take it out if it turns red then its acidic.
silver
Hydrogen gas
carbon dioxide
beryllium
magnesium chloride
Sorry if any are wrong i tried