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adoni [48]
3 years ago
10

The true value was 0.120. What was your percent error? ____ %

Chemistry
2 answers:
egoroff_w [7]3 years ago
4 0
Percent error is actual divided by theoretical. What is your theoretical value?
otez555 [7]3 years ago
3 0

Answer:

MRCORRECT has answered the question

Explanation:

what is observed value

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You prepare a solution by dissolving 3.9280 g of solid sodium hydroxide in 300 mL of distilled water in a 500 mL volumetric flas
Sindrei [870]

Answer:

0.196 M

Explanation:

First, we have to calculate the moles of sodium hydroxide.

moles = mass / molar mass

moles  = 3.9280 g / (39.997 g/mol) = 0.098207 mol

It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.

The molar concentration of sodium hydroxide is:

M=\frac{n_{solute}}{V_{solution}(L)} =\frac{0.098207 mol}{0.500L} =0.196 M

The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.

4 0
3 years ago
The reaction AB(aq)→A(g)+B(g) is second order in AB and has a rate constant of 0.0164 M −1 ⋅ s −1 at 25.0 ∘ C . A reaction vesse
uysha [10]
The reaction is second order in AB, so: v=k[AB]^2. In the statement, we obtain that [AB]=0.104~M and, at 25 ºC, k=0.0164~M^{-1}\cdot s^{-1}. Then:

v=k[AB]^2\\\\
v=0.0164\cdot0.104^2\\\\
v=0.0164\cdot0.010816\\\\
v\approx0.000177=1.77\times10^{-4}~mol/s

Now, we'll calculate the number of mols of the products in the gas. Using the Ideal Gas Law:

\bullet~\text{Pressure:}~p=707.3-23.8=683.5~mmHg\\\\
\bullet~\text{Volume:}~V=142~mL=0.142~L\\\\
\bullet~\text{Number of moles:}~n=n_A+n_B\\\\
\bullet~\text{Ideal gas constant:}~R=62.3~L\cdot mmHg\cdot K^{-1}\cdot mol^{-1}\\\\
\bullet~\text{Temperature:}~T=25^oC=25+273~K=298~K\\\\

pV=nRT\\\\
683.5\cdot0.142=n\cdot62.3\cdot298\\\\
n=\dfrac{683.5\cdot0.142}{62.3\cdot298}\\\\
n\approx0,0052~mol

Since each AB molecule forms one of A and one of B, n_A=n_B. Hence: 2n_A\approx0,0052\Longrightarrow n_A=n_B\approx0.0026~mol.

We'll consider that in the beginning there was not A or B. So, \Delta n_A=\Delta n_B=0.0026-0=0.0026~mol. Furthermore, since the ratio of AB to A and to B is 1:1, |\Delta n_{AB}|=|\Delta n_A|=|\Delta n_B|.

Calculating the time by the expression of velocity:

v=\dfrac{|\Delta[AB]|}{\Delta t}=\dfrac{1}{\Delta t}\cdot\dfrac{|\Delta n_{AB}|}{V}=\dfrac{1}{\Delta t}\cdot\dfrac{|\Delta n_A||}{250~mL}\\\\
1.77\cdot10^{-4}=\dfrac{1}{\Delta t}\cdot\dfrac{0.0026~mol}{0.25~L}\\\\
\Delta t=\dfrac{0.0026}{0.25\cdot1.77\cdot10^{-4}}\\\\
\boxed{\Delta t\approx58.76~s}
8 0
3 years ago
What structural units make up network solids
zheka24 [161]
Nonmetal Atom is the answer.
5 0
3 years ago
2 grams of hydrogen diffuses from containers in 10 minutes. How many grams of oxygen would diffuse through same container in sam
Leya [2.2K]

Answer:20

Explanation:make sure you thank me

4 0
3 years ago
Describing Diffusion
yaroslaw [1]

Answer:

its the 3rd option.

the molecules move from region of higher concentration to a region of lower concentration.

Explanation:

please do give me brainliest if this helped you.

thank you and have a great day :D

3 0
3 years ago
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