Given the wavelength of the yellow light (700 nm. in this case) we can find the frequency
<span>by dividing the speed of light c by the wavelength w, that is: f = c/w and we know that </span>
<span>c is equal to 2.998 * 10**8 meters per second. </span>
<span>So the frequency f = (2.998 * 10**8) / (7.0 * 10**-7) = 4.283 * 10**14 cycles per sec. </span>
<span>(or Hz.) Since the threshold frequency of Cs is 9.39 * 10**14 Hz, the red light doesn't </span>
<span>have a high enough frequency (or energy) to cause electron emission. </span>
<span>Hope this answers your question.</span>
Answer:
+/- 0.00033
Explanation:
For a 95 % confidence interval the range is given by
+/- Z * s/sqrt(n)
where Z value is 1.916 for a 95% confidence interval
Therefore the interval is
s is the standard deviation in this case 0.0015
n is 75 the number of outposts
calculating,
+/- 1.916 * 0.0015/sqrt(75) = +/- 0.00033
