The van can carry 6 students and bus can carry 21 students.
Step-by-step explanation:
Given,
High School A: 12 vans and 11 buses with 303 students
High School B: 6 vans and 7 buses with 183 students
To find the number of students that a van and a bus can carry.
Let us take,
The van can carry x students and the bus can carry y students.
According to the problem,
12x+11y = 303 ------- (1)
6x+7y = 183 ------- (2)
Multiplying 2 with (2) and subtract (1) and (2) we get,
(12x+11y) - 2(6x+7y) = 303-2(183)
or, 12x+11y-12x-14y = 303-366
or, -3y = -63
or, y = 21
From (2) we get,
6x+7(21) = 183
or, 6x = 183-147
or, 6x = 36
or, x = 6
Hence,
The van can carry 6 students and bus can carry 21 students.
Answer:
4:35 am
Step-by-step explanation:
change 04:35 to 12 hours clock time
An integer is a whole number. Sum means to add and since they are consecutive, there is only a difference of 1 between them.
1) 21 + 23: not consecutive
2) 23+24= 47: has to be at least 46
3) 22+23= 45: has to be at least 46
4) 24+25= 49: has to be at least 46
So we have two possibilities: either #2 or #4. Find least possible pair of integers.
x= first integer
x+1= second integer
x + (x+1) >= 46
2x + 1 >=46
2x>=45
x>=22.5
Answer:
The first integer has to be greater than or equal to 22.5. Since integers are whole numbers, round up to the next whole number. The least possible integers are #2) 23 and 24.
Hope this helps! :)
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