Answer:
1.53 atm
Explanation:
From the question given above, the following data were obtained:
Volume = constant
Initial pressure (P₁) = stp = 1 atm
Initial temperature (T₁) = 273 K
Final temperature (T₂) = 144 °C = 144 °C + 273 = 417 K
Final pressure (P₂) =?
Since the volume is constant, the final pressure can be obtained as follow:
P₁ / T₁ = P₂ / T₂
1 / 273 = P₂ / 417
Cross multiply
273 × P₂ = 417
Divide both side by 273
P₂ = 417 / 273
P₂ = 1.53 atm
Therefore, the final pressure (i.e the pressure inside the hot water bottle) is 1.53 atm.
Given buffer:
potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )
[KHC4H4O6] = 0.0451 M
[K2C4H4O6] = 0.028 M
Ka1 = 9.2 *10^-4
Ka2 = 4.31*10^-5
Based on Henderson-Hasselbalch equation;
pH = pKa + log [conjugate base]/[acid]
where pka = -logKa
In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2
pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]
= -log (4.31*10^-5) + log [0.0451]/[0.028]
pH = 4.15
Answer:D
Explanation: Solid, liquid, and gas phases in equilibrium
Answer:
The correct answer is option c. transfer of electrons from Mg to O.
Explanation:
Hello!
Let's solve this!
When Magnesium (Mg) reacts with oxygen (O), magnesium oxide is formed.
This reaction is spontaneous and occurs with oxidation number +2 of magnesium and oxidation number -2 of oxygen. It is an ionic union, so magnesium transfers its electrons to oxygen.
We conclude that the correct answer is option c. transfer of electrons from Mg to O.
Answer:
Explanation:
An element with atomic number 18 is a noble gas.
The element with atomic number 19 will have one extra electron so it can donate one electron or shed one electron to attain noble gas configuration .
It tends to shed one electron to become positively charged ion . Hence they are electro-positive elements .
Similarly the element with atomic number 17 will have one short electron so it can gain one electron to attain noble gas configuration .
They tend to gain one electron to become negatively charged ion . Hence they are electro-negative elements . They have high electronegativity .
