Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
9514 1404 393
Answer:
3/11 were left
Step-by-step explanation:
A packet of oranges is 11/11. Subtracting 4/11 +4/11 = 8/11 from that leaves ...
11/11 -8/11 = (11 -8)/11 = 3/11
3 elevenths were left.
Answer:
36
Step-by-step explanation:
you would just to 39^2-15^2 which is 1296 and the square root of that is 36 so 36 would be the answer
Answer:
Step-by-step explanation:
2q + 2p = 1 + 5q
-3q + 2p = 1
-3q = 1 - 2p
3q = 2p - 1
q = (2p -1)/3
