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PIT_PIT [208]
3 years ago
13

Which shows the best use of the associative and commutative properties to

Mathematics
1 answer:
OlgaM077 [116]3 years ago
5 0

Answer:

D

Step-by-step explanation:

So the associative and commutative properties basically say That you can change the orders of the numbers and the answer won't change (for multiplication and addition).

Your answer would be D because they added the numbers with a decimal place together, it makes it easier to look at, and add in your head.

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if P(x)=1+6x-5x^2 represents the profit in selling x thousand Boombotix speakers, how many speakers should be sold to maximize p
Rashid [163]

Answer:

600

Step-by-step explanation:

p(x) = 1 + 6x - 5x^2

x max = -b/2a

a = -5

b = 6

-6/2(-5) = 6/10 = 3/5 = .6

.6 thousand = 600

600 speakers should be sold.

Alternatively, you can check the vertex of the parabola formed.

8 0
3 years ago
Assume that the empirical rule is a good model for the time it takes for all passengers to board an airplane. The mean time is 4
slamgirl [31]

Answer:

The interval that describes how long it takes for passengers to board the middle 95% of the time is between 40.16 minutes and 55.84 minutes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 48, \sigma = 4.

Which interval describes how long it takes for passengers to board the middle 95% of the time?

This is between the 2.5th percentile and the 97.5th percentile.

So this interval is the value of X when Z has a a pvalue of 0.025 and the value of X when Z has a pvalue of 0.975

Lower Limit

Z has a pvalue of 0.025 when Z = -1.96. So

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{X - 48}{4}

X - 48 = -1.96*4

X = 40.16

Upper Limit

Z has a pvalue of 0.975 when Z = 1.96. So

Z = \frac{X - \mu}{\sigma}

1.96 = \frac{X - 48}{4}

X - 48 = 1.96*4

X = 55.84

The interval that describes how long it takes for passengers to board the middle 95% of the time is between 40.16 minutes and 55.84 minutes.

7 0
3 years ago
Granny had 25 bananas.
Ede4ka [16]

Answer:

No

Step-by-step explanation:

She needs 3 bananas for each  loaf of banana bread.

She needs 3*9=27 bananas for 9 loaves.

She has only 25, she is 2 bananas short

7 0
3 years ago
Read 2 more answers
Please could you explain this step by step I’m really stuck.
allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

  • \frac{5}{x + 3} + \frac4{x + 2} = 2
  • 5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)
  • 5 + \frac{4x + 12}{x + 2} = 2x + 6
  • 5(x + 2) +4x + 12 = (2x + 6)(x + 2)
  • 5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12
  • 9x + 22 = 2x^2 + 10x + 12

Let's make one side equal to 0.

  • 0 = 2x^2 + x - 10

Solve by factoring, and then the zero product property.

  • 0 = 2x^2 + x - 10\\

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, ax^2 + bx + c, think two numbers that equal "ac" and add up to "b".

  • 0 = 2x^2 - 4x + 5x - 10
  • 0 = 2x(x - 2) + 5(x - 2)
  • 0 = (2x + 5)(x - 2)

Using the zero product property, set each factor to 0 and solve for x.

  1. 2x + 5 = 0
    2x = -5
    x = -5/2 = -2.5
  2. x - 2 = 0
    x = 2

The two answers are x = -2.5, and x = 2.

3 0
2 years ago
Read 2 more answers
Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!
vlada-n [284]
  • In second quadrant sin and cosec are positive

\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta

\\ \tt\hookrightarrow sin^2\theta=1-(\dfrac{-2\sqrt{5}}{5})^2

\\ \tt\hookrightarrow sin^2\theta=1-\dfrac{20}{25}

\\ \tt\hookrightarrow sin^2\theta=\dfrac{5}{25}

\\ \tt\hookrightarrow sin\theta=\dfrac{\sqrt{5}}{5}

\\ \tt\hookrightarrow sin\theta=\dfrac{1}{\sqrt{5}}

5 0
2 years ago
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