Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
It is A, 1/5 hopefully i am the BRAINLIEST!!!!!
Answer:
Step-by-step explanation:
a)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,r =50
rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854
area growing 7854 cm2/s
b)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,A =64
pi r^2 =64
=>r =8/√pi
rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98
area growing 708.98 cm2/s
Answer:
6 1/6
Step-by-step explanation:
-2 1/2 * 3 1/3
-2 * -3 = 6
1/2 * 1/3 = 1/6
Answer:
attempt it, if it's too hard, sleep
that's what I would do lol
Step-by-step explanation:
