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Citrus2011 [14]
3 years ago
6

What is the factored form of 3x+24y? 3(x+8y) 3xy(x+8y) 3(3x+24y) 3xy(3x+24y)

Mathematics
2 answers:
DerKrebs [107]3 years ago
8 0

Answer:

yall its AAAAAAAA

Step-by-step explanation:

TRUST ME

Artyom0805 [142]3 years ago
5 0

Answer:

Option A. 3(x+8y)

Step-by-step explanation:

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Step-by-step explanation:

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1 year ago
Which equation is the equation of a circle with a diameter of 20 cm and center at (-3, 6)?
larisa86 [58]
The equation of a circle with centre (a,b) and radius r is:
(x - a)^2 + (y - b)^2 = r^2
thus,
here centre (a,b) = (-3,6), a = -3, b = 6
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5 0
3 years ago
Evaluate it..........​
trasher [3.6K]

Answer:

the answer is \frac{1}{41} (23x-2ln(5sinx+4cosx))

Step-by-step explanation:

\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx

here,

a=3, b=2, c=5, d=4

M=\frac{ac+bd}{c^2+d^2 }=\frac{3*5+2*4}{5^2+4^2}=\frac{23}{41}

N=\frac{bc-ad}{c^2+d^2 }=\frac{2*5-3*4}{5^2+4^2}=\frac{-2}{41}

\int {\frac{3sinx+2cosx}{5sinx+4cosx} } \, dx=\int{\frac{\frac{23}{41}(5sinx+4cosx)-\frac{2}{41}(5cosx-4sinx)  }{5sinx+4cosx} }\,dx

=\frac{23}{41}\int\, dx -\frac{2}{41} \int{\frac{5cosx-4sinx}{5sinx+4cosx} }\, dx

=\frac{1}{41} (23x-2ln(5sinx+4cosx))

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Step-by-step explanation:

7 0
3 years ago
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