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Sunny_sXe [5.5K]
3 years ago
14

certain gas occupies 6.24L at pressure of 760 mm Hg.If the pressure is reduced to 60.0mm Hg,what would the new volume be?​

Chemistry
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

79.04 L

Explanation:

We are given;

Initial Volume; V1 = 6.24L

Initial Pressure; P1 = 760 mm Hg

Final pressure; P2 = 60.0mm Hg

To solve for final volume, we will use Boyles law;

P1•V1 = P2•V2

Let's make V2 which is the final volume the subject;

V2 = (P1•V1)/P2

V2 = (760 × 6.24)/60

V2 = 79.04 L

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7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams
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Answer:

Mass = 255 g

Explanation:

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Chemical equation:

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Now we will compare the moles of nitrogen and ammonia.

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7 0
2 years ago
if a baloon filled with dry hydrogen weighs 35 gram,but weighs 440 grams when filled with the vapour of an organic compound. cal
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Answer:

1) The vapor density of the organic compound is approximately 12.57

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Explanation:

1) The mass of the balloon filled with dry hydrogen = 35 grams

The mass of the balloon filled with vapor of an organic compound = 440 grams

The vapor density = (Weight of a given volume of gas)/(Weight of equal volume of hydrogen)

The vapor density of the organic compound = (440)/(35) ≈ 12.57

The vapor density of the organic compound ≈ 12.57

2) The relative molar mass (RMM) = 2 × vapor density

The relative molar mass (RMM) of the organic compound = 2 × vapor density of the organic compound

The relative molar mass (RMM) of the organic compound ≈ 2 × 12.57 ≈ 25.14 grams  

The relative molar mass (RMM) of the organic compound ≈ 25.14 grams  

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