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nadezda [96]
3 years ago
7

AdiffusioncoupleofweldedAandBwasgivenadiffusionannealatelevatedtemperatureandthencooledtoroomtemperature.Chemicalanalysisofthesu

ccessivelayercutparalleltotheweldinterfaceshowthatoveradistanceof5000nm,NAchangedfrom0.3to0.35.Assumethatthenumberofatomsperm3ofbothpuremetalsis9×1028.a)determinetheconcentrationgradientdnA/dx,b)ifthediffusioncoefficientatthepointinquestionatannealingtemperaturewas2×10-14m2/s,determinethenumberofAatomspersecondthatwouldpassthroughthiscross-sectionattheannealingtemperature.Neglecttheinterfacemotion.
Chemistry
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

what

Explanation:

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NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.
SCORPION-xisa [38]

Answer:

NH3(aq) + HNO3(aq) → NH4NO3(aq) Calculate the volume of an acid (1.5 M HNO3) needed to neutralize the 1.5 M HNO3.

Explanation:

8 0
3 years ago
A 5 mole sample of liquid acetone is converted to a gas at 75.0°C. If 628 J are required to raise the temperature of the liquid
velikii [3]
The total energy required for this conversion is equivalent to the sum of the energies that are used. There are three steps:

1) Heating of liquid acetone
This used 628 J

2) Evaporation of acetone
This used 15.6 kJ or 15,600 J

3) Heating of acetone vapors
This used 712 J

Adding these quantities,

Total energy = 628 + 15,600 + 712

The total energy required was <span>16940 Joules of 16.94 kJ</span>
7 0
3 years ago
If you have 35 ml of gas in a closed container under 1.23 atm of pressure, what will the volume be if the pressure increased to
Over [174]

Answer:

New volume is 14.35 mL

Explanation:

When a system of a gas keeps on constant its temperature and number of moles, the pressure is modified indirectly proportional to the volume:

Pressure increased → Volume decreased

Pressure decreased → Volume increased.

The relation you have to apply is: P₁ . V₁ = P₂. V₂

1.23 atm . 35 mL = 3 atm . V₂

(1.23 atm . 35 mL / 3 atm)  = V₂

V₂ = 14.35 mL

5 0
3 years ago
Read 2 more answers
The following choices contain densities of various materials. Based on these data, which will yield the fastest seismic velocity
Eduardwww [97]

Answer:

D. 5.6 g/cm^3

Explanation:

On the average seismic velocity increases with increase in depth due higher the pressure and more compaction

sand and shales in the Niger Delta Basin density–velocity relationship is

P = 0.31×V^0.25

A derivation of the original Gardner equation to calculate the average densities for sands and shales in wells.

ρ = α ×V^β

where

ρ = bulk density in g/cm3,

V = P-wave velocity,

α = 0.31 for V (m/s) and 0.23 for V(ft/s) and

β = 0.25.

Such that

ρ = 0.31 ×V^0.25

So the fastest seismic velocity will be in the densest material which is D. 5.6 g/cm3

5 0
3 years ago
what is the molarity of a solution that has 1.54 moles NaCI in a 3.7L solution. How do you prepare 50ml of 0.5 M of KCI from a s
dsp73

Answer:

69jtententemwntsj6e

Explanation:

uegehwhb3iejebb

8 0
3 years ago
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