Answer:
Your answer will be 118 cm^3.
Explanation:
V1/T1 = V2/T2, so V2 = V1T2/T1. 60C = 333K and 120C = 393K.
V2 = (100cm3)(393K)/(333K) = 118 cm3
Answer:
1.5 mol H2O
Explanation:
2C2H6 + 7O2 -> 4CO2 + 6H2O
The limiting reactant is C2H6
30 g C2H6 ->1 mol C2H6
15 g C2H6 -> x x= 0.5 mol C2H6
2 mol C2H6 -> 6 mol H2O
0.5 mol c2H6 -> x x = 1.5 mol H2O
Answer:
The solution becomes colorless and a light blue precipitate is formed.
Explanation:
When sodium hydroxide is added to copper(II) nitrate solution, a precipitate of copper(II) hydroxide is formed.
The solution gradually becomes colorless as the light blue precipitate appears.
The reaction is complete (enough sodium hydroxide has been added) when the blue color of the solution completely disappears.
The equation of the reaction is;
Cu(NO3)2(aq) + 2NaOH(aq) → Cu(OH)2(s) + 2NaNO3(aq)
To determine the mass of the sugar molecules given, we need to convert the given value into moles by using the a constant. <span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. Then, by using the molar mass of sugar, we can convert from moles to grams. Molar mass of sugar is 342.3 g/mol. We do as follows:
</span><span>2.50 × 10^25 molecules of sugar ( 1 mol / 6.022x10^23 g ) ( 342.3 g / 1 mol) = 14210.40 grams of sugar present</span>
Answer:
pH before addition of KOH = 4.03
pH after addition of 25 ml KOH = 7.40
pH after addition of 30 ml KOH = 7.57
pH after addition of 40 ml KOH = 8.00
pH after addition of 50 ml KOH = 10.22
pH after addition 0f 60 ml KOH = 12.3
Explanation:
pH of each case in the titration given below
(6) After addition of 60 ml KOH
Since addition of 10 ml extra KOH is added after netralisation point.
Concentration of solution after addition 60 ml KOH is calculated by
M₁V₁ = M₂V₂
or, 0.23 x 10 = (50 + 60)ml x M₂
or M₂ = 0.03 Molar
so, concentration of KOH = 0.03 molar
[OH⁻] = 0.03 molar
pOH = 0.657
pH = 14 - 0.657 = 13.34
