Let one integer be x, the consecutive odd integer is x+2
reciprocals are 1/x and 1/(x+2)
1/x +1/(x+2)=24/143
make the denominators the same:
(x+2)/[x(x+2)] +x/[x(x+2)]=24/143
143(2x+2)=24(x)(x+2)
286x+286=24x²+48x
24x²-238x-286=0
use the quadratic formula: x=22 this doesn't work because 22 is not an odd number.
or x=-2.1666666666 (this is not an integer)
weird.
Answer: 6:5
Step-by-step explanation:
Your answer would be 4 over x to the sixth which would look like this
4
_
x^6
the ^ symbol means it’s an exponent
Answer:
=3–√−13–√+1⋅3–√−13–√−1
=(3–√−1)23–√2−12
=3–√2+12−23–√3−1
=4−23–√2
2−13–√
a=2,b=−1.
Step-by-step explanation:
