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miv72 [106K]
3 years ago
10

How many grams of colbalt-60 would remain at 6 half-lives?

Chemistry
1 answer:
Kay [80]3 years ago
6 0

Answer: 0.3125g

Explanation:

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John Dalton believed which of the following about atoms?
8090 [49]
Atoms are real even though they're invisible.
3 0
3 years ago
¿A qué grupo pertenecen los átomos de Z = 8, Z= 36 y Z=39? ¿Cuántas capas de electrones tiene cada uno? ¿Cuántos electrones harí
zaharov [31]

Answer:

Mira la explicación.

Explanation:

¡Hola!

En este caso, podemos encontrar facilmente el grupo al que pertenecen dichos elementos con números atómicos 8, 36 y 39 respectivamente mediante su búsqueda en la tabla periódica. Así, z=8 corresponde a oxígeno, z=36 a kriptón y z=39 a itrio.

Por otro lado, para saber el número de capas, debemos desarrollar la configuración electrónica para cada uno:

O: 1s^2,2s^2,2p^4\\Kr: 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6\\Y:1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^1

Con esto, vemos que oxígeno tiene dos capas, kripton cuatro capas e iritrio cinco, a lo que a oxígeno le faltan dos electrones para llenar dicha capa, a kripton ninguno y a iritrio nueve.

Saludos.

3 0
3 years ago
What allows composites (such as carbon-fiber-reinforced polymers) to be so strong and elastic? Select all that apply.
Elena-2011 [213]
I think there would be two correct answers from the choices listed above. These are the second and the last option. Composites are strong and elastic because of the extensive cross-linking between molecules and the <span>properties of metals and plastics. Hope this answers the question.</span>
8 0
3 years ago
Read 2 more answers
Kemmi Major does some experimental work on the combustion of sucrose: C12H22O11(s) 12 O2(g) → 12 CO2(g) 11 H2O(g) She burns a 0.
Pavlova-9 [17]

Answer: 5.81\times 10^6J/mol

Explanation:

Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

C_{12}H_{22}O_{11}(s)+12O_2\rightarrow 12CO_2(g)+11H_2O(g)

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles

Thus 1.577\times 10^{-4}moles of sucrose releases =  916.6 J of heat

1 mole of sucrose releases =\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J of heat

Thus ∆H value for the combustion reaction is 5.81\times 10^6J/mol

6 0
4 years ago
How do you write the compound Mg3N2? Are Roman numerals included as well? ​
GREYUIT [131]

Answer:

It is written exactly like that; Mg3N2

Explanation:

Roman numerals are used sometimes to show the charge of an ion that can be multiple charges.

5 0
4 years ago
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