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3 years ago

Which of the following accurately describes junction diodes?

Physics

2 answers:

tatiyna3 years ago

8 0

Correct answer choice is :

D) In a forward-biased setup, large numbers of charge carriers will be pulled across the junction and result in a large current.

Explanation:

P-n junction diode is the easiest mode of all the semiconductor tools. Despite, diodes act a significant role in many electronic appliances. A p-n junction diode can be utilized to change the alternating current to the direct current. These diodes are applied in power supply accessories. Battery attached across the p-n junction causes the diode forward biased, pushing particles from the n-type to the p-type and starting holes in a different way. Electrons and holes cross the junction and join. Photons are carried off as the electrons and holes recombine.

vovangra [49]3 years ago

8 0

D. In forward-biased setup, large numbers of charge carriers will be pulled across the junctions and result in a large current

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A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. The girl then slows

Alona [7]

Answer:

1) The girl's acceleration at time 't' is, $a=0.47$ m/s²

2) The girl's acceleration at time 't₁' is, $a_{1}=0$ m/s²

3) The girl's acceleration at time 't₂' is, $a_{2}=-0.14$ m/s²

Explanation:

Given data,

The initial walking speed of the girl, u = 0

The speed of the girl at the time 't' 3 s is, v₁ = 1.4 m/s

The time period the girl walked at the speed 1.4 m/s is, t₁ = 6 s

The girl slows down and comes to a stop during a period, t₂ = 10 s

1) The girl's acceleration at time 't'

$a=\frac{v-u}{t}$

$a=\frac{1.4-0}{3}$

$a=0.47$ m/s²

2) The girl's acceleration at time 't₁'

$a_{1} =\frac{v_{1} -v}{t_{1}}$

$a_{1}=\frac{1.4-1.4}{6}$

$a_{1}=0$ m/s²

3) The girl's acceleration at time 't₂'

$a_{2} =\frac{v_{2} -v_{1}}{t_{2}}$

$a_{2}=\frac{0-1.4}{10}$

$a_{2}=-0.14$ m/s²

4 0

3 years ago

What exercise will strengthen your legs?

Olin [163]

Answer: Squats and leg lifts

Explanation:

They strengthen your legs!

7 0

3 years ago

6. How would the measurements for potential difference and current change if a 200 Ω resistor was used in Circuit 1 instead of t

Maksim231197 [3]

Answer:

Explanation:

Resistance is defined as the opposition to the flow of an electric current in a circuit. This means that a higher amount of resistance tends to reduce the amount of current flowing through the resistance. The lower the current, the greater the possibility for the resistor to allow current to pass through it. if a 200 Ω resistor was used in Circuit 1 instead of the 100 Ω resistor, then the current in the circuit will tends to increase since we are replacing the load with a lesser resistor and a smaller resistance tends to allow more current to flow through it

For the potential difference, a decrease in the resistance value will onl decrease the potential difference flowing in the circuit according to ohm's law. According to the law the pd in a circuit is directly proportional to the current which means an increase in the resistance value will cause an increase in the corresponding pd and vice versa.

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3 years ago

A car slows from 27 m/s to 5 m/s with a constant acceleration for 6.87 s. What is the car’s acceleration?

Kobotan [32]

In this case, the movement is uniformly delayed (the final rapidity is less than the initial rapidity), therefore, the value of the acceleration will be negative.

1. The following equation is used:

a = (Vf-Vo)/ t

a: acceleration (m/s2)

Vf: final rapidity (m/s)

Vo: initial rapidity (m/s)

t: time (s)

2. Substituting the values in the equation:

a = (5 m/s- 27 m/s)/6.87 s

3. The car's acceleration is:

a= -3.20 m/ s<span>^2</span>

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3 years ago

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Triss [41]

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Explanation:

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2 years ago