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3 years ago

25 POINTS PLS ANSWER

Chemistry

1 answer:

VMariaS [17]3 years ago

6 0

Answer:

The answer would be methane if the problem is asking for the fastest

Explanation:

I hope this helps answer your question

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Chemistry, need answer ASAP!! 50 points and i'll mark brainliest if correct! ^w^

pishuonlain [190]

Answer:

615 g

Explanation:

In order to convert from moles of any given substance into grams, we have to use said substance's molar mass, as follows:

# moles * Molar mass = grams of substance.

Thus, we now calculate the molar mass of beryllium iodide, BeI₂, using the molar masses of the elements:

Molar Mass of BeI₂ = Molar Mass of Be + (Molar Mass of I)*2 = 262.821 g/mol

Finally we calculate how many grams are there in 2.34 moles of BeI₂:

2.34 mol * 262.821 g/mol = 615 g

4 0

2 years ago

What is sodium bicarbonate an example of? a buffer an acid a liquid a base

ludmilkaskok [199]

Answer:

base

Explanation:

carbonic acid - H2CO3 - is a weak acid. Therefore, HCO3 itself is its conjugate base. The Na(sodium) ion is neutral.

This means that NaHCO3 is a base. (a weak one)

3 0

2 years ago

600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c

Ludmilka [50]

Answer:

$k=1.20x10^{-3} s^{-1}$

Explanation:

For a first order reaction the rate law is:

$v=\frac{-d[A]}{[A]}=k[A]$

Integranting both sides of the equation we get:

$\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt$

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

$ln\frac{[A]}{[A]_{0} } =-kt$

$[A]=[A]_{0}e^{-kt}$

$ln[A]=ln[A]_{0} -kt$

$k=\frac{ln[A]_{0}-ln[A]}{t}$

therefore k is

$k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}$

8 0

3 years ago

how do the properties of compounds compare to the properties of the elements from which they are composed

Crank

The elements that form the compound don't compare because it doesn't matter about the elements when they are combined. The elements that formed it together is completely different than the outcome compound.

6 0

2 years ago

what volume of a 0.155 M calcium hydroxide solution is required to neutralize 28.8 mL of a 0.106 M nitric acid?

Hitman42 [59]

Answer:

9.85mL

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

Ca(OH)2 + 2HNO3 —> Ca(NO3)2 + 2H2O

From the balanced equation above,

nA (mole of the acid) = 2

nB (mole of the base) = 1

Data obtained from the question include:

Vb (volume of the base) =?

Mb (Molarity of base) = 0.155 M

Va (volume of the acid) = 28.8 mL

Ma (Molarity of acid) = 0.106 M

Using MaVa/MbVb = nA/nB, the volume of calcium hydroxide (i.e the base) can be obtain as follow:

MaVa/MbVb = nA/nB

0.106 x 28.8 / 0.155 x Vb = 2/1

Cross multiply to express in linear form as shown below:

2 x 0.155 x Vb = 0.106 x 28.8

Divide both side by 2 x 0.155

Vb = (0.106 x 28.8) / (2 x 0.155)

Vb = 9.85mL

Therefore, the Volume of calcium hydroxide is 9.85mL

7 0

2 years ago