this should be it hope it helps Cu2(OH)2CO3
The source below says 35.89g of NaCl dissolve in 100 g of water at 20 °C.
<span>(35.89g / 100 mL) x (2000 mL) = 718 g
Hope this helped </span>
C6H15, C2H5 has a molar mass of 29g/mol. 87 divided by 29 is 3. Then multiply each element subscript by 3
Answer: The freezing point depression is 
Explanation:
Depression in freezing point is given by:
= Depression in freezing point
= freezing point constant = 
m= molality = 
Thus freezing point depression is
First we calculate the concentration of HCl:
Moles = mass / Mr
= 25 / 36.5
= 0.685 mol
Concentration = 0.685/1.5 = 0.457 mol / dm³
For a strong monoprotic acid, the concentration of hydrogen ions is equal to the acid concentration.
pH = -log[H+]
pH = -log(0.457)
= 0.34
