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VladimirAG [237]
1 year ago
6

a chemist has a block of iron metal (density is 7.87 g/ml). the block weighs 1.90 g. what is the volume of the iron block in ml?

Chemistry
1 answer:
Natali5045456 [20]1 year ago
6 0

The block of iron metal with a density of 7.87 g/mL has a volume in mL of 0.2414 mL

The density formula and the procedure we will use is:

ρ = m/v

Where:

  • v= volume
  • ρ= density
  • m= mass

Information about the problem:

  • m= 1.90 g
  • ρ= 7.87 g /mL
  • v= ?

Applying the density formula and clearing the volume (v), we get:

ρ = m/v

v = m / ρ

v = 1.90 g / 7.87 g/ mL

v = 0.2414 mL

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

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When 229.0 J of energy is supplied as heat to 3.00 mol of Ar(g) at constant pressure the temperature of the sample increases by
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Answer:

The molar heat capacity at constant volume is 21.62 JK⁻¹mol⁻¹

The molar heat capacity at constant pressure is 29.93 JK⁻¹mol⁻¹

Explanation:

We can calculate the molar heat capacity at constant pressure from

C_{p,m} = \frac{C_{p} }{n}

Where C_{p,m} is the molar heat capacity at constant pressure

{C_{p} } is the heat capacity at constant pressure

and n is the number of moles

Also {C_{p} } is given by

{C_{p} } = \frac{\Delta H}{\Delta T}

Hence,

C_{p,m} = \frac{C_{p} }{n} becomes

C_{p,m} = \frac{\Delta H }{n \Delta T}

From the question,

\Delta H = 229.0 J

n = 3.00 mol

\Delta T = 2.55 K

Hence,

C_{p,m} = \frac{\Delta H }{n \Delta T} becomes

C_{p,m} = \frac{229.0}{(3.00) (2.55)}

C_{p,m} = 29.93 JK⁻¹mol⁻¹

This is the molar heat capacity at constant pressure

For, the molar heat capacity at constant volume,

From the formula

C_{p,m} = C_{v,m} + R

Where C_{v,m} is the molar heat capacity at constant volume

and R is the gas constant (R = 8.314 JK⁻¹mol⁻¹)

Then,

C_{v,m} = C_{p,m}  - R

C_{v,m} = 29.93 - 8.314

C_{v,m} = 21.62 JK⁻¹mol⁻¹

This is the molar heat capacity at constant volume

5 0
3 years ago
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