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2 years ago

In ABC with the right angle at vertex C, sin(b)= (26)/8. What is sin(a)?

Mathematics

1 answer:

Marat540 [252]2 years ago

4 0

Answer:

We can use the Pythagorean theorem and properties of sines, cosines, and tangents to solve the triangle, that is, to find unknown parts in terms of known parts.

Step-by-step explanation:

Pythagorean theorem: a2 + b2 = c2.

Sines: sin A = a/c, sin B = b/c.

Cosines: cos A = b/c, cos B = a/c.

Tangents: tan A = a/b, tan B = b/a.

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Heather took one of her friends out to lunch. The lunches cost $100 and she paid 9% sales tax. If Heather left a 15% tip on the

Allushta [10]

Answer:

124 is the total

Step-by-step explanation:

100 * .09 = 9

100 * .15 = 15

15+ 9 + 100 = 124

Hope it helps!

7 0

3 years ago

Find the volume of the cylinder.

Vaselesa [24]

Answer:

160pi

Step-by-step explanation:

the volume of a cylinder is found using the formula V=pi x r² x h. taking r=4 this means we have pi x 16 x10 =160pi

8 0

2 years ago

Max claims that a point on any line that is perpendicular to a segment is equidistant from a segment's endpoints. Charlene claim

yan [13]

Answer:

Charlene claim is true.

Step-by-step explanation:

Max claims that a point on any line that is perpendicular to a segment is equidistant from a segment's endpoints.

It is not necessary as shown in the diagram (a).

Charlene claims that the line must be a perpendicular bisector for a point on the line to be equidistant from a segment's endpoints.

It is true as shown in the diagram (b).

So, Charlene claim is true.

3 0

2 years ago

Can someone help me

goldfiish [28.3K]

Answer:

0,4,8,12,16

Step-by-step explanation:

so for the value of x- just substitute it into the equation

so -2

8+4(-2)

8-8=0

7 0

3 years ago

PQR is a right angled triangle calculate the size of angle marked x

romanna [79]

Answer:

$\displaystyle x \approx 37.4^\circ$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Define

Angle θ = x

Adjacent Leg = 5.8

Hypotenuse = 7.3

Step 2: Solve for x

Substitute in variables [Cosine]: $\displaystyle cosx^\circ = \frac{5.8}{7.3}$
[Fraction] Divide: $\displaystyle cosx^\circ = 0.794521$
[Equality Property] Trig inverse: $\displaystyle x^\circ = cos^{-1}(0.794521)$
Evaluate trig inverse: $\displaystyle x = 37.39^\circ$
Round: $\displaystyle x \approx 37.4^\circ$

8 0

2 years ago