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3 years ago

Crude oil is a mixture of many different chemical compounds.

Chemistry

1 answer:

evablogger [386]3 years ago

6 0

Answer:

092) Icosane

093) Ethene

Explanation:

092) The given compounds are;

Decane C₁₀H₂₂; Viscosity = 0.850 mPa·s (25°C)

Ethene C₂H₄ (gas); Viscocity ≈ 0.01038 m

Icosane C₂₀H₄₂; Solid at room temperature

Methane CH₄; gas at room temperature

The viscosity of the given carbon and hydrogen compounds is observed to increase with their molar masses

Therefore, icosane, which is a solid at room temperature, has the highest viscosity (resistance to deformation) out of the given compounds

093) Polymers are made from monomer alkene units, therefore, ethene, which is the only alkene among the given compounds can be used to produce a polymer

Polyethene is formed by the polymerization of ethene whereby molecules of ethene are joined together to form poly(ethene)

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If the take off velocity of an airplane on a runway is 300 km /hr with an acceleration of 1 m/s2. What is the take off time of t

Rama09 [41]

<h3>Answer:</h3>

83.33 seconds.

<h3>Explanation:</h3>

<u>We are given;</u>

Take off velocity as 300 km/hr
Acceleration as 1 m/s²

We are required to calculate the take off time of the airplane.

<h3>Step 1: Convert velocity from km/hr to m/s </h3>

We are going to use the conversion factor.

The conversion factor is 3.6 km/hr per m/s

Therefore;

Velocity = 300 km/hr ÷ 3.6 km/hr per m/s

= 83.33 m/s

<h3>Step 2: Calculate the take off time</h3>

We know that;

v = u + at

where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

But, initial velocity is Zero

Therefore;

83.33 m/s = 1 m/s² × t

Thus;

time = 83.33 m/s ÷ 1 m/s²

= 83.33 seconds

Therefore, the take off time is 83.33 seconds.

5 0

3 years ago

What will most likely happen when a component is removed from a reaction system at equilibrium?

Sever21 [200]

Answer:

it's C

Explanation:

the equilibrium sytem will shift to remove more of what was removed

8 0

3 years ago

2. If I have 45 g of Carbon, to find the number of moles of carbon I would *

Sati [7]

Answer:

divide by molar mass (12.01 g)

Explanation:

To find the number of moles of the carbon, divide by molar mass (12.01 g).

The number of moles of a substance is given as;

Number of moles = $\frac{mass}{molar mass}$

To solve this problem;

since mass of carbon = 45g

Number of moles = $\frac{45}{12.01}$ = 3.75moles

3 0

3 years ago

Read 2 more answers

Dissolving potassium chlorate (KClO3) is even more endothermic than potassium chloride.

zhenek [66]

Answer:

The mass of KClO₃ that will absorb the same heat as 5 g of KCl is 3.424 g

Explanation:

Here we have

Heat of solution of KClO₃ = + 41.38 kJ/mol.

Heat of solution of KCl (+17.24 kJ/mol)

Therefore, 1 mole of KCl absorbs +17.24 kJ during dissolution

Molar mass of KCl = 74.5513 g/mol

Molar mass of KClO₃ = 122.55 g/mol

74.5513 g of KCl absorbs +17.24 kJ during dissolution, therefore, 5 g will absorb

$\frac{17.24}{74.5513 } \times 5 \, \, kJ \, or \, 1.156 \, kJ$

Therefore the amount of KClO₃ to be dissolved to absorb 1.156 kJ of energy is given by

122.55 g of KClO₃ absorbs + 41.38 kJ, therefore,

$\frac{1.156}{41.38} \times 122.55 \, g = 3.424 \, g$

Therefore the mass of KClO₃ that will absorb the same heat as 5 g of KCl = 3.424 g.

5 0

3 years ago

All the substances listed below are fertilizers that contribute nitrogen to the soil.

kvv77 [185]

Answer:

Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.

Explanation:

Percentage of element in compound :

$=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100$

(a) Urea, $(NH_2)_2CO$

Molar mass of urea = 60 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 2

$N\%=\frac{2\times 14 g/mol}{60 g/mol}\times 100=46.67\%$

(b) Ammonium nitrate, $NH_4NO_3$

Molar mass of ammonium nitrate = 80 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 2

$N\%=\frac{2\times 14 g/mol}{80 g/mol}\times 100=35.00\%$

(c) Nitric oxide, NO

Molar mass of nitric oxide = 30 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 1

$N\%=\frac{1\times 14 g/mol}{30 g/mol}\times 100=46.67\%$

(d) Ammonia, $NH_3$

Molar mass of ammona = 17 g/mol

Atomic mass of nitrogen = 14 g/mol

Number of nitrogen atoms = 1

$N\%=\frac{1\times 14 g/mol}{17 g/mol}\times 100=82.35\%$

Ammonia is the richest source of nitrogen on a mass percentage basis because it has 82.35% of nitrogen by mass.

4 0

3 years ago