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uysha [10]
3 years ago
9

A 25.00 mL sample of sulfuric acid solution from an automobile battery reacts completely with 87.42 mL of a 1.95 M solution of p

otassium hydroxide. What is the molar concentration of the battery?
Chemistry
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

[H₂SO₄] = 6.82M

Explanation:

This is a sort of neutralization reaction:

A strong acid with a strong base to produce water and the correspondent salt.

H₂SO₄  +  2NaOH →  Na₂SO₄ + 2H₂O

Formula for neutralization is: M acid . volume acid = M base . volume base

M acid . 25 mL = 1.95 M . 87.42 mL

M acid = (1.95 M . 87.42 mL) / 25 mL → 6.82M

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25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃

Explanation:

Based on the reaction of the problem, 1 mole of Fe₂S₃ is produced from 2 moles of FeCl₃.

0.345g of Fe₂S₃ are (Molar mass: 207.9g/mol):

0.345g of Fe₂S₃ ₓ (1 mol / 207.9g) = <em>1.6595x10⁻³ moles Fe₂S₃</em>

Moles of Fe needed to produce these moles of Fe₂S₃ are:

1.6595x10⁻³ moles Fe₂S₃ ₓ ( 2 moles FeCl₃ / 1 mole Fe₂S₃) =

<em>3.3189x10⁻³ moles of FeCl₃</em>

As the percent yield of the reaction is 65.0%, the moles of FeCl₃ you need to add are:

3.3189x10⁻³ moles of FeCl₃ ₓ (100.0% / 65.0%) = <em>5.106x10⁻³ moles of FeCl₃</em>

A solution 0.200M contains 0.200 moles per L. Volume to obtain 5.106x10⁻³ moles is:

<em>5.106x10⁻³ moles of FeCl₃ ₓ ( 1L / 0.200mol) = 0.02553L = </em>

<h3>25.53mL of 0.200 M FeCl₃ are needed to produce 0.345g of Fe₂S₃</h3>

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