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uysha [10]
3 years ago
9

A 25.00 mL sample of sulfuric acid solution from an automobile battery reacts completely with 87.42 mL of a 1.95 M solution of p

otassium hydroxide. What is the molar concentration of the battery?
Chemistry
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

[H₂SO₄] = 6.82M

Explanation:

This is a sort of neutralization reaction:

A strong acid with a strong base to produce water and the correspondent salt.

H₂SO₄  +  2NaOH →  Na₂SO₄ + 2H₂O

Formula for neutralization is: M acid . volume acid = M base . volume base

M acid . 25 mL = 1.95 M . 87.42 mL

M acid = (1.95 M . 87.42 mL) / 25 mL → 6.82M

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A chemist dissolves of pure potassium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (The t
Leya [2.2K]

Answer:

12.99

Explanation:

<em>A chemist dissolves 716. mg of pure potassium hydroxide in enough water to make up 130. mL of solution. Calculate the pH of the solution. (The temperature of the solution is 25 °C.) Be sure your answer has the correct number of significant digits.</em>

Step 1: Given data

  • Mass of KOH: 716. mg (0.716 g)
  • Volume of the solution: 130. mL (0.130 L)

Step 2: Calculate the moles corresponding to 0.716 g of KOH

The molar mass of KOH is 56.11 g/mol.

0.716 g × 1 mol/56.11 g = 0.0128 mol

Step 3: Calculate the molar concentration of KOH

[KOH] = 0.0128 mol/0.130 L = 0.0985 M

Step 4: Write the ionization reaction of KOH

KOH(aq) ⇒ K⁺(aq) + OH⁻(aq)

The molar ratio of KOH to OH⁻is 1:1. Then, [OH⁻] = 0.0985 M

Step 5: Calculate the pOH

We will use the following expression.

pOH = -log [OH⁻] = -log 0.0985 = 1.01

Step 6: Calculate the pH

We will use the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 -1.01 = 12.99

8 0
3 years ago
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