Question

The mass of solute per 100 mL of solution is abbreviated as (m/v). Mass is not technically the same thing as weight, but the abbreviation (w/v) is also common. How many grams of sucrose are needed to make 715 mL of a 39.0% (w/v) sucrose solution?

Answer 1

Answer:

Amount of sucrose required = 278.85 g

Explanation:

(w/v)% = 39.0 %

Volume of the solution = 715 mL

39% (w/v) means 39 g of sucrose present in 100 mL of the solution.

Using unitary method,

For making 39% solution,

100 mL solution requires 39 g of the sucrose

therefore, 715 mL solution requires:

                                                $715\;mL \times\frac{39\;g}{100\;mL}$

                                                = 278.85 g