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FrozenT [24]
4 years ago
12

Anna is selling boxes of chocolate chip cookies (c) for $6 each and boxes of peanut butter cookies (b) for $7 each. She must

Mathematics
1 answer:
Georgia [21]4 years ago
7 0

Answer:

x+y\geq30

6c+7b\geq175

Step-by-step explanation:

Given : Let c represents the number of boxes of chocolate chip cookies and b represents the boxes for butter cookies.

Anna is selling boxes of chocolate chip cookies (c) for $6 each and boxes of peanut butter cookies (b) for $7 each.

i.e. Cost of 'c' chocolate chip cookies = 6c

Cost of b butter cookies = 7b

She must  sell at least 30 boxes of cookies and at least $175 worth of cookies.

i.e. x+y\geq30

6c+7b\geq175

Thus , the system of inequalities models this situation :

x+y\geq30

6c+7b\geq175

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Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

<u>Assumptions:</u>

The sample size (<em>n</em>) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean <em>p</em> and standard deviation \sqrt{\frac{p(1-p)}{n} } .

Since the sampling distribution of sample proportions follows a normal distribution use the <em>z</em>-test for one proportion to perform the test.

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H_{0} : The proportion of U.S. households that owned two or more televisions is 83%, i.e. p=0.83

H_{1} :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. p< 0.83

<u>Decision Rule:</u>

At the level of significance α = 0.05 the critical region for a one-tailed <em>z</em>-test is:

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<u>Test statistic value:</u>

z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

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Now compute the value of the test statistic as follows:

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The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

<u>Conclusion:</u>

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is  83%.

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