All categories

3 years ago

Anna is selling boxes of chocolate chip cookies (c) for $6 each and boxes of peanut butter cookies (b) for $7 each. She must

Mathematics

1 answer:

Georgia [21]3 years ago

7 0

Answer:

$x+y\geq30$

$6c+7b\geq175$

Step-by-step explanation:

Given : Let c represents the number of boxes of chocolate chip cookies and b represents the boxes for butter cookies.

Anna is selling boxes of chocolate chip cookies (c) for $6 each and boxes of peanut butter cookies (b) for $7 each.

i.e. Cost of 'c' chocolate chip cookies = 6c

Cost of b butter cookies = 7b

She must sell at least 30 boxes of cookies and at least $175 worth of cookies.

i.e. $x+y\geq30$

$6c+7b\geq175$

Thus , the system of inequalities models this situation :

$x+y\geq30$

$6c+7b\geq175$

You might be interested in

50 points to whoever can answer!

Pavlova-9 [17]

Answer:

Step-by-step explanation:

I think I'm not sure about that

4 0

3 years ago

16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0

3 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

3 years ago

Question On picture 100 points please help

NARA [144]

Answer:

B is a table and the x-axis is 12 as the area

Step-by-step explanation:

3 0

3 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago