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brilliants [131]
3 years ago
9

Solve the following system of equations using substitution.

Mathematics
1 answer:
ollegr [7]3 years ago
7 0

To solve system of equations by substitution, we are going to use the first equation to substitute into the second equation wherever you see y.

5x - 4y = -3

5x - 4(3x-5) = -3

5x -12x+20=-3

               -20     -20  

_______________

5x-12x=-23

-7x=-23

___    ____

 -7       -7

x=3.29 (rounded)

Next, substitute x = 3.29 into the first equation, or to any equation you'd like, to find y.

y = 3x-5

y = 3(3.29)-5

y = 9.87-5

y = 4.87

So, your final answer would be (3.29, 4.87).

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Rate of change of profit for this period = $2750 / month
4 0
3 years ago
Which of the following statements is true for the logistic differential equation?
solong [7]

Answer:

All of the above

Step-by-step explanation:

dy/dt = y/3 (18 − y)

0 = y/3 (18 − y)

y = 0 or 18

d²y/dt² = y/3 (-dy/dt) + (1/3 dy/dt) (18 − y)

d²y/dt² = dy/dt (-y/3 + 6 − y/3)

d²y/dt² = dy/dt (6 − 2y/3)

d²y/dt² = y/3 (18 − y) (6 − 2y/3)

0 = y/3 (18 − y) (6 − 2y/3)

y = 0, 9, 18

y" = 0 at y = 9 and changes signs from + to -, so y' is a maximum at y = 9.

y' and y" = 0 at y = 0 and y = 18, so those are both asymptotes / limiting values.

8 0
3 years ago
I need help plz I don't get this problem
OlgaM077 [116]
To find the answer you need to write equivalent fractions with larger denominators. If you multiply each fraction by 3/3 then your equivalent fractions would be

3/5 × 3/3 = 9/15
4/5 × 3/3 = 12/15

Now we have two fractions that are equivalent to the original fractions and we can easily see that 2 fractions between 9/15 and 12/15 would be...

10/15 and 11/15

(10/15 can reduce to 2/3 so your answers could also be 2/3 and 11/15)
5 0
3 years ago
Can u show 4 divided 4 with a rectangle
Lady bird [3.3K]
I just showed you 5556666666
5 0
3 years ago
Can someone help with these two answer
gayaneshka [121]

Answer:

5. 2¯⁶ or 1/2⁶

6. 2⁹

Step-by-step explanation:

5. Simplify 2⁴ ÷ 2¹⁰

The above expression can be simplified as follow:

2⁴ ÷ 2¹⁰

Recall

Aⁿ ÷ Aᵐ = Aⁿ¯ᵐ

Thus,

2⁴ ÷ 2¹⁰ = 2⁴ ¯ ¹⁰

2⁴ ÷ 2¹⁰ = 2¯⁶

Recall:

A¯ⁿ = 1/Aⁿ

Thus,

2¯⁶ = 1/2⁶

Therefore,

2⁴ ÷ 2¹⁰ = 2¯⁶ or 1/2⁶

6. Simplify 2³ × (2²)³

2³ × (2²)³ can be simplified as follow:

2³ × (2²)³

Recall

(Aⁿ)ᵐ = Aⁿ*ᵐ

Thus,

(2²)³ = 2²*³

(2²)³ = 2⁶

2³ × (2²)³ = 2³ × 2⁶

Recall

Aⁿ × Aᵐ = Aⁿ⁺ᵐ

2³ × 2⁶ = 2³⁺⁶

2³ × 2⁶ = 2⁹

Therefore,

2³ × (2²)³ = 2⁹

5 0
3 years ago
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