Right click! It seems easy enough but, I'm required to put 20 characters =/
Answer:
Declaration for function 1:
void printHeading(String heading);
Declaration for function 2:
int yearPage(int currentYear, int birthYear);
Declaration for function 3:
void printable(String [] names, int [] birthDays, int size);
Explanation:
Prototypes of any function includes its return type followed by its name followed by list of arguments used by it enclosed within parenthesis.
Syntax for method declaration:
return_type function_name (list_of_arguments);
Answer:
c. it prevents the packet from remaining indefinitely in the network thus helping to prevent network congestion
Explanation:
It prevents the packet from remaining indefinitely in the network thus helping to prevent network congestion
TTL is a value which is shown so that we can estimate that the packet that will tell the network router whether the packet has been in the network for enough time so that it should be discarded from the network or not.
Answer:
i am still a beginner in this but i hope it helps.
- add scanner object;
- declare string FavColour;
- print msg to ask user for input
- print msg (" your favourite colour is " + FavColour)
In this program, I am using the school-based grading system and the program should accept the subject and the number of students.
Program approach:-
- Using the necessary header file.
- Using the standard I/O namespace function.
- Define the main function.
- Declare the variable.
- Display enter obtain marks in 5 subjects.
- Return the value.
Program:-
//header file
#include<iostream>
//using namespace
using namespace std;
//main method
int main()
{
//declare variable
int j;
float mark, sum=0, a;
//display enter obtain marks in 5 subjects
cout<<"Enter Marks obtained in 5 Subjects: ";
for(j=0; j<5; j++)
{
cin>>mark;
sum = sum+mark;
}
a = sum/5;
//display grade
cout<<"\nGrade = ";
if(a>=91 && a<=100)
//display a1
cout<<"a1";
else if(a>=81 && a<91)
//display a2
cout<<"a2";
else if(a>=71 && a<81)
cout<<"b1";
else if(a>=61 && a<71)
cout<<"b2";
else if(a>=51 && a<61)
//display c1
cout<<"c1";
else if(a>=41 && a<51)
//display c2
cout<<"c2";
else if(a>=33 && a<41)
//display d
cout<<"d";
else if(a>=21 && a<33)
//display e1
cout<<"e1";
else if(a>=0 && a<21)
//display e2
cout<<"e2";
else
//display invalid
cout<<"Invalid!";
cout<<endl;
//return the value
return 0;
}
Learn more grading system
brainly.com/question/24298916
