2 years ago

Proportional relationship

Mathematics

1 answer:

iragen [17]2 years ago

7 0

Answer:

I'm pretty sure it's B

Step-by-step explanation:

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1 year ago

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Setler [38]

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2 years ago

A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation o

olasank [31]

Answer:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

Step-by-step explanation:

Information given

$\bar X=9.41$ represent the sample mean

$s=0.24$ represent the sample standard deviation

$n=81$ sample size

$\mu_o =9.33$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:

Null hypothesis: $\mu \leq 9.33$

Alternative hypothesis: $\mu > 9.33$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

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2 years ago

Please help me I don’t know this

inessss [21]

Answer:

28 degrees

Step-by-step explanation:

68 = 2m + 12

56 = 2m

m = 28 degrees

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2 years ago