Answer: The percent ionization of 
in a 0.050 M 
solution is 8.9 %
Explanation:
cM 0 0
So dissociation constant will be:
Give c= concentration = 0.050 M and 
= degree of ionisation = ?
Putting in the values we get:
percent ionisation =
Answer:
2.951 × 10⁻⁵ M
Explanation:
Let's consider the acid reaction of hydrobromic acid according to Brönsted-Lowry acid-base theory.
HBr(aq) + H₂O(l) ⇒ Br⁻(aq) + H₃O⁺(aq)
Given the pH = 4.530, we can calculate the concentration of the hydronium ion using the following expression.
pH = -log [H₃O⁺]
[H₃O⁺] = antilog -pH = antilog -4.530 = 2.951 × 10⁻⁵ M
im pretty sute the answer would be number 4.
mark brainliest :)
Answer:
14 mol e⁻
Explanation:
Step 1: Write the balanced half-reaction for the reduction of permanganate to manganese
8 H⁺(aq) + 7 e⁻ + MnO₄⁻(aq) ⇒ Mn(s) + 4 H₂O(l)
Step 2: Calculate the moles corresponding to 110 g of manganese
The molar mass of Mn is 55 g/mol.
110 g × 1 mol/55 g = 2 mol
Step 3: Calculate the number of moles of electrons needed to produce 2 moles of Mn
According to the half-reaction, 7 moles of electrons are required to produce 1 mole of Mn.
2 mol Mn × 7 mol e⁻/1 mol Mn = 14 mol e⁻
