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2 years ago

Give three examples, from the lab, where potential energy was converted to kinetic energy.

Chemistry

1 answer:

GREYUIT [131]2 years ago

4 0

Give 3 Examples of where potential energy was converted to knlinetic energy:

Curtain

A ball before moving

An apple from the tree then falling down

When the Curtains are still, we call the that potential energy. If you move the curtains around, that is kinetic energy

The ball is still, that is potential energy. Then the ball is moving, the is kinetic energy

There is a apple ganging from a tree, that is potential energy. That apple is fall, this is kinetic energy

Hope this helps

Don't type or write in the answer, I'm not sure what from the lab means. These are a few potential into kinetic energy I could have think of!

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Methylene chloride is less dense than water

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3 years ago

A cylinder of argon contains 50 L of Ar at 12.4 atm and 127°C . How many moles of argon are in the cylinder

joja [24]

Answer:

18.9 moles

Explanation:

We have the following data:

V = 50 L

P = 12.4 atm

T= 127°C + 273 = 400 K

R = 0.082 L.atm/K.mol (it is the gas constant)

We use the ideal gas equation to calculate the number of moles n of the gas:

PV = nRT

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3 years ago

What ionic bond occurs between what particles?

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3 years ago

A 360. g iron rod is placed into 750.0 g of water at 22.5°C. The water temperature rises to 46.7°C. What was the initial tempera

Grace [21]

Answer: The initial temperature of the iron was $515^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of iron = 360 g

$m_2$ = mass of water = 750 g

$T_{final}$ = final temperature = $46.7^0C$

$T_1$ = temperature of iron = ?

$T_2$ = temperature of water = $22.5^oC$

$c_1$ = specific heat of iron = $0.450J/g^0C$

$c_2$ = specific heat of water= $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]$

$T_i=515^0C$

Therefore, the initial temperature of the iron was $515^0C$

4 0

3 years ago

a gas has a volume of 750ml at pressure of 2.15atm what will the pressure be if the volume is 1.25ml

Dmitry [639]

Answer:

1290 atm

Explanation:

P1V1=P2V2

P2= (P1V1)/V2

P2=(2.15 atm * 750 mL)/(1.25 mL)

P2=1290 atm

6 0

3 years ago