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ladessa [460]
3 years ago
15

Two volatile liquids A (P A pure= 165 Torr) and B (PB pure= 85.1 Torr) are confined in a piston/cylinder assembly. Initially onl

y the liquid phase is present. As the external pressure is reduced, vapor is first observed at a total pressure of 110 Torr. Calculate the mole fraction of component A in the solution (XA) and the mole fraction of component A in the vapor (YA).
Chemistry
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

y_A=0.467\\x_A=0.312

Explanation:

Hello,

In this case, one could use the following equations to compute the required mole fractions (fugacity equality for both A and B):

p_A^{vap}x_A=y_AP\\p_B^{vap}(1-x_A)=(1-y_A)P\\p_B^{vap}-x_Ap_B^{vap}=P-y_AP\\y_AP-x_Ap_B^{vap}=P-p_B^{vap}

Therefore, the 2x2 system of equations turns out:

\left \{ {{165x_A-110y_A=0} \atop {110y_A-85.1x_A=24.9}} \right.\\ \\y_A=0.467\\x_A=0.312

Best regards.

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Explanation:

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2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

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                     x = (19.36 x 1) / 12

                     x = 1.61 moles

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                      x = (77.39 x 1)/16

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Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

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