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Harlamova29_29 [7]
3 years ago
5

Leader Corporation Company uses a job-order costing system with a single plantwide pre-determined overhead rate based on machine

-hours. The 98554-CZ company based its pre-determined overhead rate for the current year on the following data:
Total machine-hours 50,000
Total fixed manufacturing overhead cost $400,000
Variable manufacturing overhead per machine-hour $6
Recently, Job D168 was completed with the following characteristics:
Number of units in the job 40
Total machine-hours 100
Direct materials $750
Direct labor cost $2,750
If the company marks up its unit product costs by 60% then the selling price for a unit in Job D168 is closest to:____.
a. $2,505.
b. $3,025.
c. $1,185.
d. $2,360.
Business
1 answer:
taurus [48]3 years ago
3 0

Answer:

Selling price per unit= $196

Explanation:

<u>First, we need to calculate the predetermined overhead rate:</u>

<u></u>

Predetermined manufacturing overhead rate= total estimated overhead costs for the period/ total amount of allocation base

Predetermined manufacturing overhead rate= (400,000 / 50,000) + 6

Predetermined manufacturing overhead rate= $14 per machine hour

<u>Now, we can allocate overhead and calculate the total cost:</u>

<u></u>

Allocated MOH= Estimated manufacturing overhead rate* Actual amount of allocation base

Allocated MOH= 14*100= $1,400

Total cost= 1,400 + 750 + 2,750

Total cost= $4,900

<u>Finally, the selling price per unit:</u>

<u></u>

Unitary cost= 4,900/40= $122.5

Selling price= 122.5*1.6

Selling price= $196

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Give an example of a situation in which a surplus of a product led to decreased prices. similarity, give a example of a situatio
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Answer:

The Linear programming model is given as below

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Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

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Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
3 years ago
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