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Stolb23 [73]
2 years ago
13

PLEASE HELP ME 10 POINTS

Mathematics
1 answer:
Furkat [3]2 years ago
5 0
B is 3, m is 0.75 x is number of miles
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A cannon ball is launched at 6 feet per second from the top of a platform 12 feet above the ground.
AleksAgata [21]
A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12

b.) The y-intercept is 12

c.) The y-intercept represent the height of the ball at time t = 0

d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
7 0
3 years ago
BRCA1 is a gene that has been linked to breast cancer. Researches at Stanford University wanted to estimate what proportion of w
Evgesh-ka [11]

Answer:

The point estimate for the proportion of women with BRCA1 mutation is 0.168

Step-by-step explanation:

The point estimate for the proportion of women with BRCA1 mutation is the number of women with this mutation divided by the size of the sample.

Of the 173, they found that 29 had BRCA1 mutations.

29/173 = 0.168

The point estimate for the proportion of women with BRCA1 mutation is 0.168

7 0
3 years ago
What is the total amount of RS.7500 at the rate of 5.5% per annum in 42 months?find it.
QveST [7]

Answer:

Please check out the attachments below to get the answer

7 0
3 years ago
Explain how to use the unit-factor method to convert 120 pounds to kilograms.
blagie [28]

Answer:

Step-by-step explanation:

lets remember that 1kg=2.2 lb

if

2.2 lbs................................1 kg

120lbs...................................? kg

120/2.2=54.54 kg

7 0
2 years ago
A jet flew for 2 hrs before strong head winds reduced its speed by 40mph. If it took the plane 5 hrs to travel 1,380 miles, find
GarryVolchara [31]

As per the problem

A jet flew for 2 hrs before strong head winds reduced its speed by 40 mph.

It took the plane 5 hrs to travel 1,380 miles

Total time=5 hrs, Time of fly before headwinds=2,

Time of fly in headwinds=5-2=3  hrs

Let the speed before head winds =v\\

Then speed in headwinds=(v-40)\\

As we know that

\text{Distance =Speed*Time}\\ \\

Hence using this formula and the given data we can write

1380=2v+3(v-40)\\ \\ \text{Simplify we get}\\ \\ 3v-120+2v=1380\\ \\ 5v=1380+120\\ \\ 5v=1500\\ \\ v=300mph\\

Hence speed before flying into the headwinds=300mph

3 0
2 years ago
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