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Arte-miy333 [17]
3 years ago
14

Simplify y^3*y^-5 write your answer using only positive exponents

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0

Answer:

y^(3_5)= y^(-2)=1/(y^2 )

final answer: 1/(y^2)

Goshia [24]3 years ago
3 0

Answer:

y2

Step-by-step explanation:

"y3"   was replaced by   "y^3".  1 more similar replacement(s).

Simplify: y5 by y3

1.1    y5 divided by y3 = y(5 - 3) = y2

Final answer:

y2

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Rose bought a bag of potatoes for $6.00 and some granola bars for $5.25 per package. Her total bill was $74.25. How many package
neonofarm [45]

Answer:

Rose bought 14 packages of granola bars.

Step-by-step explanation:

Total bill = 1 bag of potatoes + x amount of packages of granola bars

Total bill = $74.25

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We set the equation to:

74.25 = 6.00 + 5.25x

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68.25 = 5.25x

Divide both sides by 5.25 to leave x by itself

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This means Rose bought 13 packages of granola bars.

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7 0
2 years ago
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
3 years ago
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