Answer:
The answer is -1.8
Step-by-step explanation:
5 x -1.8 = -9 = -9 divided by -1.8 = 5
Answer:
(a)123 km/hr
(b)39 degrees
Step-by-step explanation:
Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.
Distance = Speed X Time
Therefore: PQ =50km/hr X 2 hr =100 km
It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.
Distance, QA=50km/hr X 2.5 hr =125 km
Using alternate angles in the diagram:

(a)First, we calculate the distance traveled, PA by plane Y.
Using Cosine rule

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am
Time taken =1.5 hour
Therefore:
Average Speed of Y

(b)Flight Direction of Y
Using Law of Sines
![\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)](https://tex.z-dn.net/?f=%5Cdfrac%7Bp%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7Bq%7D%7B%5Csin%20Q%7D%5C%5C%5Cdfrac%7B125%7D%7B%5Csin%20P%7D%20%3D%5Cdfrac%7B184.87%7D%7B%5Csin%20110%7D%5C%5C123%20%5Ctimes%20%5Csin%20P%3D125%20%5Ctimes%20%5Csin%20110%5C%5C%5Csin%20P%3D%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5C%5CP%3D%5Carcsin%20%5B%28125%20%5Ctimes%20%5Csin%20110%29%20%5Cdiv%20184.87%5D%5C%5CP%3D39%5E%5Ccirc%20%24%20%28to%20the%20nearest%20degree%29)
The direction of flight Y to the nearest degree is 39 degrees.
Answer:
1)= 1 kilogram per liter (kg/l) + 8.35 pound per gallon (lb/gal)
2)= 4.4704 meters per seconds
3)= 12in= 1ft ratio is 12:1
4)= 1ft=12in ratio is 1:12
5)= 3ft= 1 yard ratio is 3:1
6)=1 yard = 3ft ratio 1:3
Step-by-step explanation:
12 in = 1 foot
1 yard = 3 feet
1 yard = 36 in
I hope this helps
Answer:
f³(x) = 64/x⁶
Step-by-step explanation:
f³(x) = (f(x))³ = (4/x²)³ = 4³/(x²)³
f³(x) = 64/x⁶
_____
The applicable rules of exponents are ...
(a/b)^c = (a^c)/(b^c)
(a^b)^c = a^(bc)
X is equal to about 3.218876