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3 years ago

How the government support communities affected by xenophobia

Chemistry

2 answers:

Ann [662]3 years ago

8 0

Answer:

They tax the citizens and then provide them with relief efforts

Explanation:

Common disease protocol

fgiga [73]3 years ago

7 0

Heytggt did did did dk did did did r eeueueieuwo said that he was a member of the new acc party

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Which of the following are advantages of the SI system?

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The correct answer is A, B and C

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The diagram below shows a box with

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The answer is: D the box will NOT move or change. Hope this helps!

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3 years ago

Determine the molarity of a 6.0 mole% sulfuric acid solution with SG-a 1.07 Note: Atomic Weight: S (32), O 16); H (O)

marin [14]

Answer:

The molarity of a 6.0 mole% sulfuric acid solution is 2.8157 Molar.

Explanation:

Suppose there are 100 moles in solution:

Moles of sulfuric acid = 6% of 100 moles = 6 moles

Mass of 6 moles of sulfuric acid = 6 mol × 98 g/mol=588 g

Moles of water = 100%- 6% = 94%= 94 moles

Mass of water = 94 mol × 18 g/mol = 1692 g

Specific gravity of the solution ,S.G= 1.07

Density of solution = D

$S.G=\frac{D}{d_w}$

$d_w$ = density of water = 1 g/mL

$D=S.G\times d_w=1.07\times 1 g/mL=1.07 g/mL$

Mass of the solution = 588 g + 1692 g = 2280 g

Volume of the solution = V

Volume = $\frac{Mass}{Density}$

$=\frac{2280 g}{1.07 g/mL}=2130.84 mL=2.13084 L$

1 mL = 0.001 L

$Molarity = \frac{n}{V(L)}$

n = number of moles of compound

V = volume of the solution in L

here we have ,n = 6 moles of sulfuric acid

V = 2.13084 L

So, the molarity of the solution is :

$Molarity=\frac{6 mol}{2.13084 L}=2.8157 mol/L$

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3 years ago

What do noble gases all have in common?

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Answer:

D. They react readily with oxygen in the air

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2 years ago

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

labwork [276]

First convert grams to moles using molar mass of butane that is 58.1 g

3.50g C4H10 x (1 mol C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 

Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol C4H10) = 3.627x10^22 molecules C4H10

And there are 4 carbon atoms in 1 molecule of butane, so use the following ratio:

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule C4H10)
= 1.45 x 10^23 atoms of carbon are present

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3 years ago

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How the government support communities affected by xenophobia​

How the government support communities affected by xenophobia