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Mice21 [21]
1 year ago
15

Find the pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00).

Chemistry
1 answer:
Lostsunrise [7]1 year ago
4 0

The pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00) is 9.82. As

pH = 10 + log ([1.2]/[1.8]) = 9.82.

<h3>What is sodium phenolate?</h3>

An organic chemical with the formula NaOC6H5 is sodium phenoxide. It is a crystalline white substance. The conjugate base of phenol is its anion, phenoxide, sometimes referred to as phenolate. It serves as a base for several other chemical substances, including aryl ethers. The solid form of sodium phenolate is a white to reddish-tinted solid that resembles crystalline rods. They are used in chemical synthesis and as an antiseptic. It performs a cleansing function. Typically, it dissolves in water. The resultant solutions have pH values higher than 7.0 and contain moderate amounts of hydroxide ions. To neutralize acids, they respond as bases.

To learn more about sodium phenolate, visit:

brainly.com/question/15262075

#SPJ4

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A gaseous mixture contains 443.0 Torr H 2 ( g ) , 369.9 Torr N 2 ( g ) , and 82.7 Torr Ar ( g ) . Calculate the mole fraction, χ
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Answer:

χH₂ = 0.4946

χN₂ = 0.4130

χAr = 0.0923

Explanation:

The total pressure of the mixture (P) is:

P = pH₂ + pN₂ + pAr

P = 443.0 Torr + 369.9 Torr + 82.7 Torr

P = 895.6 Torr

We can find the mole fraction of each gas (χ) using the following expression.

χi = pi / P

χH₂ = pH₂ / P = 443.0 Torr/895.6 Torr = 0.4946

χN₂ = pN₂ / P = 369.9 Torr/895.6 Torr = 0.4130

χAr = pAr / P = 82.7 Torr/895.6 Torr = 0.0923

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