Answer:
CaS, CaBr₂, VBr₅, and V₂S₅.
Explanation:
- The ionic compound should be neutral; the overall charge of it is equal to zero.
- Binary ionic compound is composed of two different ions.
<u>Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.
- CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.
<u>V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.</u>
- V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.
- VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.
<em>So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.</em>
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Is it250 degrees c if so it would be <span> 4.66 moles</span>
explain the question your asking
Answer is: <span>the mass of the glucose is 81,07 grams.
</span>c(C₆H₁₂O₆) = 0,3 M = 0,3 mol/L.
V(C₆H₁₂O₆) = 1,500 L.
n(C₆H₁₂O₆) = c(C₆H₁₂O₆) · V(C₆H₁₂O₆).
n(C₆H₁₂O₆) = 0,3 mol/L · 1,5 L.
n(C₆H₁₂O₆) = 0,45 mol.
m(C₆H₁₂O₆) = n(C₆H₁₂O₆) · M(C₆H₁₂O₆).
m(C₆H₁₂O₆) = 0,45 mol · 180,156 g/mol.
m(C₆H₁₂O₆) = 81,07 g.
Answer:
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Explanation:
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