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Mice21 [21]
1 year ago
15

Find the pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00).

Chemistry
1 answer:
Lostsunrise [7]1 year ago
4 0

The pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00) is 9.82. As

pH = 10 + log ([1.2]/[1.8]) = 9.82.

<h3>What is sodium phenolate?</h3>

An organic chemical with the formula NaOC6H5 is sodium phenoxide. It is a crystalline white substance. The conjugate base of phenol is its anion, phenoxide, sometimes referred to as phenolate. It serves as a base for several other chemical substances, including aryl ethers. The solid form of sodium phenolate is a white to reddish-tinted solid that resembles crystalline rods. They are used in chemical synthesis and as an antiseptic. It performs a cleansing function. Typically, it dissolves in water. The resultant solutions have pH values higher than 7.0 and contain moderate amounts of hydroxide ions. To neutralize acids, they respond as bases.

To learn more about sodium phenolate, visit:

brainly.com/question/15262075

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What is another name for a coefficient? this is for chemistry
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Answer:

synergistic

Explanation:

Synergistic means: relating to the interaction or cooperation of two or more organizations, substances, or other agents to produce a combined effect greater than the sum of their separate effects

7 0
3 years ago
A solution is prepared by mixing 2.17 g of an unknown non-electrolyte with 225.0 g of chloroform. The freezing point of the resu
Deffense [45]

Answer:

The molar mass of the unknown non-electrolyte is 64.3 g/mol

Explanation:

Step 1: Data given

Mass of an unknown non-electrolyte = 2.17 grams

Mass of chloroform = 225.0 grams

The freezing point of the resulting solution is –64.2 °C

The freezing point of pure chloroform is – 63.5°C

kf = 4.68°C/m

Step 2: Calculate molality

ΔT = i*kf*m

⇒ ΔT = The freezing point depression = T (pure solvent) − T(solution) = -63.5°C + 64.2 °C = 0.7 °C

⇒i = the van't Hoff factor = non-electrolyte = 1

⇒ kf = the freezing point depression constant = 4.68 °C/m

⇒ m = molality = moles unknown non-electrolyte / mass chloroform

0.7 °C = 1 * 4.68 °C/m * m

m = 0.150 molal

Step 3: Calculate moles unknown non-electrolyte

molality = moles unknown non-electrolyte / mass chloroform

Moles unknown non-electrolyte = 0.150 molal * 0.225 kg

Moles unknown non-electrolyte = 0.03375 moles

Step 4: Calculate molecular mass unknown non-electrolyte

Molar mass = mass / moles

Molar mass = 2.17 grams / 0.03375 moles

Molar mass = 64.3 g/mol

The molar mass of the unknown non-electrolyte is 64.3 g/mol

6 0
3 years ago
Match the function to the part of the cell.
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3 years ago
How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?
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Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C ×  17.3°C

Q = 2640.96 J

5 0
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