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1 year ago

Find the pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00).

1 answer:

4 0

The pH of a buffer that consists of 1.3 M sodium phenolate (C₆H₅ONa) and 1.2 M phenol (C₆H₅OH) (pKₐ of phenol = 10.00) is 9.82. As

pH = 10 + log ([1.2]/[1.8]) = 9.82.

<h3>What is sodium phenolate?</h3>

An organic chemical with the formula NaOC6H5 is sodium phenoxide. It is a crystalline white substance. The conjugate base of phenol is its anion, phenoxide, sometimes referred to as phenolate. It serves as a base for several other chemical substances, including aryl ethers. The solid form of sodium phenolate is a white to reddish-tinted solid that resembles crystalline rods. They are used in chemical synthesis and as an antiseptic. It performs a cleansing function. Typically, it dissolves in water. The resultant solutions have pH values higher than 7.0 and contain moderate amounts of hydroxide ions. To neutralize acids, they respond as bases.

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Explain how muscle cells, blood cells and small intestine cells work together to keep the body moving.

spayn [35]

Answer:

Cells are considered the fundamental units of life. The cells in complex multicellular organisms like people are organized into tissues, groups of similar cells that work together on a specific task. ... At each level of organization—cells, tissues, organs, and organ systems—structure is closely related to function.

Hope this is helpful :)

5 0

2 years ago

Use the pictures below to answer the following question what type of bond is this

mezya [45]

I literally hate chem but I think it’s ionic, I’m not not completely sure but it kinda sounds about right . Not the best anwser haha hope it kinda helps lol

4 0

2 years ago

You carefully weigh out 16.00 g of CaCO3 powder and add it to 64.80 g of HCl solution. You notice bubbles as a reaction takes pl

bulgar [2K]

Answer: Mass of $CO_2$ produced in this reaction was 6.56 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CaCO_3(s)+2HCl(aq)\rightarrow H_2O(l)+CO_2(g)+CaCl_2(aq)$

Mass or reactants = Mass of $CaCO_3$ + mass of $HCl$ = 16.00 + 64.80 = 80.80 g

Mass of products = mass of aqueous solution + mass of $CO_2$ + = 74.24 + x g

Mass or reactants = Mass of products

80.80 g = 74.24 + x g

x = 6.56 g

Thus mass of $CO_2$ produced in this reaction was 6.56 grams

7 0

3 years ago

PLEASE HELP ME I NEED HELP

Crazy boy [7]

Answer:

5 moles S x (36.02 g S/mole S) = 180.1 grams of S

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element. The relationship is known as Avogadro's Number. This number, 6.02x $10^{23}$ , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than 6.02x $10^{23}$ . The mole is correlated to the atomic mass of that element. The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units. But it can also be read as 36.02 grams/mole.

This means that 36.02 grams of S contains 1 mole (6.02x $10^{23}$ ) of S atoms.

This relationship holds for all the elements. Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole. ^5.38 grams of Zn contains 1 mole of Zn atoms.

And so on.

5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = 180.1 grams of S

Note how the units cancel to leaves just grams. The units are extremely helpful in mole calculations to insure the correct mathematical operation is done. To find the number of moles in 70 g of S, for example, we would write:

(70g S)/(36.02 grams S/mole S) = 1.94 moles of S. [Note how the units cancel to leave just moles]

4 0

1 year ago

What is the electron configuration for magnesium (Mg)?

AveGali [126]

Magnesium has atomic no 12

Electronic configuration given by

1s²2s²2p⁶3s²

[Ne]3s²

6 0

1 year ago