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3 years ago

How many moles of water are needed to react with 2.2 moles of li2o? given: li2o + h2o â 2 lioh?

1 answer:

5 0

Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.

Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O

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Advantage of modern perodic law

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Answer:

it has made the study of chemistry systematic and easy. it acts as an aid to memory

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2 years ago

How to convert f to c without a calculator

nikdorinn [45]

Answer:

Without a calculator, there are many means to convert Celsius to Fahrenheit. Multiply the Celsius temperature by 1.8 and add 32 to get the Fahrenheit conversion With this method you get the exact temperature conversion degree.

Explanation:

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3 years ago

Find the element. Plz help!

Hunter-Best [27]

Answer:

Hydrogen.

Explanation:

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4 0

2 years ago

During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2

ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol = 12.81 grams

Step 6: Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = 75.70 grams CO2

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = 34.29 grams

3 0

3 years ago

A biologist has two brine solutions, one containing 4% salt and another containing 16% salt. How many milliliters of each soluti

agasfer [191]

Answer:

400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed

Explanation:

Let's assume concentration of brine salt solutions are in %(w/v) unit.

Final mixture has a concentration of 11.2% salt and volume of 1 L or 1000 mL

Hence, amount of salt in final mixture = $\frac{11.2\times 1000}{100}g=112g$

Suppose x mL of 4% salt solution and (1000-x) mL of 16% salt solution need to be mixed to get final mixture

So, amount of salt in x mL of 4% salt solution = $\frac{4x}{100}g$

amount of salt in x mL of 16% salt solution = $\frac{16\times (1000-x)}{100}g$

Hence, $\frac{4x}{100}+\frac{16\times (1000-x)}{100}=112$

or, $x=400$

So, 400 mL of 4% salt solution and 600 mL of 16% salt solution need to be mixed

3 0

3 years ago