The percentage composition of this compound : 40%Ca, 12%C and 48%O
<h3>Further explanation</h3>
Given
20.0 g of calcium,
6.0 g of carbon,
and 24.0 g of oxygen.
Required
The percentage composition
Solution
Total mass of compound :
=mass calcium + mass carbon + mass oxygen
=20 g + 6 g + 24 g
=50 g
Percentage composition :
According to the reversible reaction equation:
2Hi(g) ↔ H2(g) + i2(g)
and when Keq is the concentration of the products / the concentration of the reactants.
Keq = [H2][i2]/[Hi]^2
when we have Keq = 1.67 x 10^-2
[H2] = 2.44 x 10^-3
[i2] = 7.18 x 10^-5
so, by substitution:
1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2
∴[Hi] = 0.0033 M
I THINK it's <span>1,1-Difluorononane, or </span>
.<span>
</span>
Answer:
They are solid (with the exception of mercury, Hg, a liquid).
They are shiny, good conductors of electricity and heat.
They are ductile (they can be drawn into thin wires).
They are malleable (they can be easily hammered into very thin sheets).
If this satisfies you please consider giving me brainliest :)
Answer:
M = 0.23 M
Explanation:
Given data:
Molarity of solution = ?
Mass of NH₄Br = 4.50 g
Volume of solution = 213 mL (213 mL× 1L /1000 mL = 0.213 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of NH₄Br:
Number of moles = mass/molar mass
Number of moles = 4.50 g / 97.94 g/mol
Number of moles = 0.05 mol
Molarity:
M = 0.05 mol/ 0.213 L
M = 0.23 M
