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Marat540 [252]
3 years ago
5

In a senior class, 17% play chess, 31% play checkers, and 11% play both. Find the probability of a senior who plays chess also p

lays checkers
Mathematics
1 answer:
umka21 [38]2 years ago
7 0

Answer:

18.6%

Step-by-step explanation:

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This is geometry plz
Sergio039 [100]

Answer:

Step-by-step explanation:

a line parallel to the equation would have the same slope (7/8)

so what we know so far is

y = 7/8x + b

since it has to go through point C (-4, 8)

we’ll plug in those values for x and y (x = -4, y = 8)

8 = 7/8(-4) + b

8 = -28/8 + b

8 = -3.5 + b

b = 11.5

so the equation is

y = 7/8x + 11.5

7 0
3 years ago
Linear equations
saw5 [17]

Answer:

Ethan started of with 246,000 Twitter followers

Step-by-step explanation: 12,000 x 4 = 48,000

48,000 + 198,000 = 246,000


3 0
3 years ago
A motorcycle raced around a track at a speed of 110 miles per hour.
hammer [34]
If it’s going 110mph, and the question if asking how many mph will it go for half an hour. Simply just take 110 divided by 2.
Which gives u 55
4 0
3 years ago
Anna is organizing 40 sheets of red and blue scrapbook paper. She places 15 blue sheets in each of 2 folders. Then she splits th
Art [367]
What equations are you using for this question?
8 0
4 years ago
Read 2 more answers
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
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