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Lady bird [3.3K]
3 years ago
8

When warm air is forced upward along a cold front what might happen?

Chemistry
1 answer:
mote1985 [20]3 years ago
8 0

Answer: With the cold front, warm air is rapidly forced upward (like the shavings) in advance of the actual front (the “cutter”), creating towering cumulus clouds, some hard showers and quite possibly a few gusty thunderstorms followed by a push of cooler and drier air in its wake.

Explanation:

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What is the total number of oxygen atoms represented in the formula na2c03.10h2o?
Wewaii [24]

As per the given chemical formula- Na2CO3.10H2O, one mole of the chemical compound contains 13 moles of oxygen atoms. Hence

Number of moles of oxygen atoms in one mole of Na2CO3.10H2O = 13

number of moles of oxygen atoms in 0.2 moles of Na2CO3.10H2O = 13 X 0.2 = 2.6

Now, one mole of a substance contains 6.022 X 10^23 particles of the substance. Thus

number of atoms of oxygen in one mole of oxygen atom = 6.022 X 10^23

number of moles of oxygen atoms in 2.6 moles of oxygen atoms = 2.6 X 6.022 X 10^23 = 15.657 X 10^23

= 1.566 X 10^24

Thus, there are 1.566 X 10^24 atoms of oxygen in 0.2 moles of Na2CO3.10H2O.
4.7
7 0
3 years ago
Do free electrons appear anywhere in the balanced equation for a redox reaction?
Andru [333]

Yes, free electrons appear in balanced redox reaction equations. However, this is only true for half-reactions. This is because redox reactions primarily involve the transfer of electrons, which are better visualized if explicitly shown in the balanced reactions. In reduction reactions, electrons are placed on the left side of the equation. Oxidation reactions show electrons on the right side of the equation.


Explanation:

A half reaction is either the chemical reaction or reduction reaction part of an oxidoreduction reaction. A half reaction is obtained by considering the amendment in chemical reaction states of individual substances concerned within the oxidoreduction reaction. Half-reactions are usually used as a way of leveling oxidoreduction reactions.The half-reaction on the anode, wherever chemical reaction happens, is Zn(s) = Zn2+ (aq) + (2e-).

The metal loses 2 electrons to create Zn2+. The half-reaction on the cathode wherever reduction happens is Cu2+ (aq) + 2e- = Cu(s).

Here, the copper ions gain electrons and become solid copper.

4 0
3 years ago
Read 2 more answers
Please help me !!!!!!!!! <br> i'll give brainlist !
qwelly [4]

Answer:

A-B

C-D

E-F

I think it's these because Potential Energy increase when the graph increases and remain constant when the graph is flat.

8 0
3 years ago
What is the compound name of S3I9?
klasskru [66]
Trisulfur nonaiodide

Step-by-step explanation:
The name for a binary molecular compound has the form
Multiplying prefix+name of first element multiplying prefix+stem of second element element+ide (two words)
The multiplying prefixes for three and nine are tri and nona, respectively.
The stem of iodine is iod.
Put them together, and the name of S₃I₉ is
trisulfur nonaiodide.
4 0
3 years ago
Read 2 more answers
Please am confused and need help​
alex41 [277]

Answer:

1.  C

2.  C

3.  A

4.  C

5.  True

6.  C

Explanation:

1. C  The answer is conduction because the heat was transferred through direct contact.

2. C  The answer convection because the heat was transferred through a medium (liquid/gas).

3. A  The answer is conduction because the heat was transferred through direct contact.

4. C  The answer is radiation because the heat was transferred through thermal emission.

5. True.  This is because the air that is warmed rises, causing the cool air to replace it.  You can picture it like the scenario in question 2.

6. C  

3 0
3 years ago
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