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m_a_m_a [10]
2 years ago
5

Element

Chemistry
1 answer:
salantis [7]2 years ago
7 0

Answer:

Explanation:

This is not the exact definition of a formula unit, but I think I know what is meant. You want the number of mols that 33.8 grams represents.

1 mol of SrF2

1 unit of Sr =                     87.62

2 units of F = 19.00 * 2<u> = 38.00</u>

1 mol of SrF2          =       125.62

mols SrF2 = given mass / molar mass

given mass = 33.8

Molar mass = 125.62

mols = 33.8/125.62  = 0.269

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Why is magnification important to the study of life science?
trapecia [35]

Answer:

magnification makes everything smaller so you can see smaller things up close and study them more

Explanation:

5 0
2 years ago
The ksp of lead iodide is 7.1 × 10-9. a chemical engineer adds 0.0025 mol of ki to a solution of 0.00004 mol pb(no3)2 in 500 ml
inn [45]
Answer is: n<span>o, because the ion product is less than the Ksp of lead iodide. </span>

Chemical dissociation 1: KI(s) → K⁺(aq) + I⁻(aq).
Chemical dissociation 2: Pb(NO₃)₂(s) → Pb²⁺(aq) + 2NO₃⁻(aq).
Chemical reaction: Pb²⁺(aq) + 2I⁻(aq) → PbI₂(s).
Ksp(PbI₂) = 7.1·10⁻⁹.
V = 500 mL ÷ 1000 mL/L = 0.5 L.
c(KI) = c(I⁻) = 0.0025 mol ÷ 0.5 L.
c(I⁻) = 0.005 M.
c(Pb(NO₃)₂) = c(Pb²⁺) = 0.00004 mol ÷ 0.5 L.
c(Pb²⁺) = 0.00008 M.
Q = c(Pb²⁺) · c(I⁻)².
Q = 8·10⁻⁵ M · (5·10⁻³ M)².
Q = 2·10⁻⁹; <span> the ion product.</span>

8 0
2 years ago
I went for a walk the other day. I went four blocks east, then seven blocks south, then one block west and finally
nalin [4]

Answer:

a) distance is 4+7+1+8=20 blocks

b) displacement is 10 blocks

Explanation:

find displacement: x and y

x axis displacement = 4-1 = 3 blocks

y axis displacement = -7+8= 1 block

displacement = the square root of 3^2 + 1^2

= 9+1 = 10 blocks.

You can find the angle of displacement with respect to the initial position using trig identities, if you wish.

4 0
2 years ago
These questions are from an experiment where we had a mixture of Ferrocene, acetylferrocene and diacetyl ferrocene and we separa
PilotLPTM [1.2K]

Answer:

Explanation:

The polarity of the 3 compounds would be in the order of

Ferrocene < Acetylferrocene < Diacetylferrocene

Your TLC data has to also support this observation . This can be checked by measuring the values of Rf ( Retention factor = distance travelled by solute/solvent ) .The Rf values also has to follow this particular order: -

Ferrocene > acetylferrocene > diacetylferrocene

2) Hexane happens to be a non-polar solvent. The polarity of hexane can be increased if some polar solvents for example, ethyl and methylene chloride etc are added

Therefore, in the increasing order of solvents polarity, we have

Hexane < 1:1 mixture of hexane: methylene chloride < 9:1 mixture of methylene chloride:

3) Chromatographic techniques all have a stationary phase in addition to a mobile phase. In the case of column chromatography, the silica gel will be the stationary phase and the solvent that will be poured will be the mobile phase.

4) The TLC and column chromatography both happen to have the same stationary phase which is the silica gel. Also, the same solvent mixture is used in both the techniques. This makes the result of the 2 to be almost the same. The difference seen between them is that, TLC works against the gravity while on the other hand column chromatography works in the direction of the gravity.

5) The key feature in the IR spectra of the acetylferrocene that will be absent in the spectra of ferrocene is the presence of carbonyl stretching frequency at close to 1700 per cm(cm-1). This peak is easily differentiated between both acetyl ferrocene and ferrocene.

4 0
2 years ago
4.60 mL of 0.1852 M HNO3 is titrated to the phenolphthalein indicator endpoint with 27.35 mL of a KOH solution. What is the mola
Kamila [148]

Answer:

M_{base}=0.0311M

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

n_{acid}=n_{base}

Which in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the base (KOH) to obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M

Regards!

4 0
2 years ago
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