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m_a_m_a [10]
2 years ago
5

Element

Chemistry
1 answer:
salantis [7]2 years ago
7 0

Answer:

Explanation:

This is not the exact definition of a formula unit, but I think I know what is meant. You want the number of mols that 33.8 grams represents.

1 mol of SrF2

1 unit of Sr =                     87.62

2 units of F = 19.00 * 2<u> = 38.00</u>

1 mol of SrF2          =       125.62

mols SrF2 = given mass / molar mass

given mass = 33.8

Molar mass = 125.62

mols = 33.8/125.62  = 0.269

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3. What would be the effect of bringing a basketball that was inflated indoors outside on a freezing winter
erica [24]

Answer:

it would go back to being deflated

4 0
3 years ago
Butane, C4H10 burns in oxygen. How many grams of water vapor, H2O, are produced by the combustion of 580 grams of butane at stan
zepelin [54]

Answer:

The answer to your question is 900 g of water vapor

Explanation:

Data

mass of H₂O = ?

mass of butane = 580 g

Balanced chemical reaction

             2C₄H₁₀ + 13O₂  ⇒  8CO₂  +  10H₂O

Process

1.- Calculate the molar weight of butane and water

Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]

                         = 2[48 + 10]

                         = 2[58]

                         = 116 g

Water (H₂O) = 10[(1 x 2) + (1 x 16)]

                    = 10[2 + 16]

                    = 10[18]

                    = 180 g

2.- Use proportions and cross multiplication to find the mass of water vapor

             116 g of butane ------------- 180 g of water

             580 g of butane  ----------  x

                x = (580 x 180) / 116

                x = 900 g of water vapor

3 0
3 years ago
One mole of neon, a monatomic gas, starts out at conditions of standard temperature and pressure. the gas is heated at constant
Anna71 [15]
<span>We can use the ideal gas law PV=nRT For the first phase The starting temperature (T1) is 273.15K (0C). n is 1 mole, R is a constant, P = 1 atm, V1 is unknown. The end temperature (T2) is unknown, n= 1 mol, R is a constant, P = 3*P1= 3 atm, V2=V1 Since n, R, and V will be constant between the two conditions: P1/T1=P2/T2 or T2= (P2*T1)/(P1) so T2= (3 atm*273.15K)/(1 atm)= 3*273.15= 816.45K For the second phase: Only the temperature and volume change while n, P, and R are constant between the start and finish. So: V1/T1=V2/T2 While we don't know the initial volume, we know that V2=2*V1 and T1=816.45K So T2=(V2*T1)/V1= (2*V1*T1)/V1=2*T1= 2*816.45K= 1638.9K To find the total heat added to the gas you need to subtract the original amount of heat so 1638.9K-273.15K= 1365.75K</span>
6 0
3 years ago
A vessel with a volume of 32. 5 l contains 2. 80 g of n2 gas, 0. 403 g of h2 gas, and 79. 9 g of ar gas. at 25°c, what is the to
d1i1m1o1n [39]

The total pressure of the gases in the vessel is found out by using the partial pressures of individual gases and adding them up. The total pressure of the gases in the vessel is 1.72 atm.

The Partial pressure of the gases is the individual pressure of the gases present in a vessel containing a mixture of gases. The total pressure can be found out by adding partial pressure of all gases.

Given:

Volume of vessel, V= 32.5L

Mass of Nitrogen gas = 2.8g

Mass of Hydrogen gas = 0.403g

Mass of Argon gas = 79.9g

We know that:

             Molar Mass of Nitrogen gas = 28g

             Molar Mass of Hydrogen gas = 2g

             Molar Mass of Argon gas = 40g

∴ Moles of gas = Given mass / Molar mass

∴ Using the Ideal Gas Equation:

PV = nRT

where, P is the Pressure of gas

V is the volume of gas

n is the moles of gas

R is the Universal Gas constant

T is the temperature

Applying the above equation of all three gases indivudually,

∴ For Nitrogen,

P₁V = n₁RT                    

⇒ P₁ × 32.5 = 2.8/28 × 0.082 × 298

⇒ P₁ = 0.07atm

∴ For Hydrogen,

P₂V = n₂RT                    

⇒ P₂ × 32.5 = 0.4/2 × 0.082 × 298

⇒ P₂ = 0.15 atm

∴ For Argon,

P₃V = n₃RT                    

⇒ P₃ × 32.5 = 79.9/40 × 0.082 × 298

⇒ P₃ = 1.5 atm

∴ Total pressure of vessel, P = P₁ + P₂ + P₃

                                         P = 1.72 atm

The total pressure of the gases in the vessel is 1.72 atm.

Learn more about Partial pressure here, brainly.com/question/23841760

#SPJ4

6 0
1 year ago
October 15, 2018 at 1:49 PM Dioxybenzone is a compound found in sunscreen, and only contains carbon, oxygen, and hydrogen. Analy
-Dominant- [34]

Answer:

Molecular formula for Dioxybenzone is C₁₄H₁₂O₄

Explanation:

Percent composition:

In 100 g of compound → 4.92 g are H

In 100 g of compound → 26.8 g are O

In 100 g of compound → 68.28 g are C

Let's convert the mass to moles by molar mass:

4.92 g / 1 g/mol = 4.92 moles H

26.8 g / 16 g/mol = 1.67 moles O

68.28 g / 12 g/mol = 5.69 moles C

Now we can apply a rule of three:

100 g of compound have 4.92 moles H, 1.67 moles O, 5.69 moles C

244.25 g of compound must have:

(244.25 g . 4.92 m) / 100 g = 12 moles H

(244.25 g . 1.67 m) / 100 g = 4 moles O

(244.25 g . 5.69 m) / 100 g = 14 moles of C

4 0
3 years ago
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