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9966 [12]
3 years ago
8

65.39Atomic # =Atomic Mass =# of Protons =# of Neutrons =# of Electrons =​

Chemistry
1 answer:
ratelena [41]3 years ago
8 0

Answer:

The answer to your question is below

Explanation:

Atomic mass = 65.39 g

Searching this number in the periodic table we find that the element is Zinc.

Then:

# of Protons = 30

# of neutrons = atomic mass - # of protons

                       = 65.39 - 30

                        = 35.39

# of electrons = # of protons = 30

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Convert 3 mol of Co, to grams.
GuDViN [60]

Answer:

176.7996 grams

Explanation:

Molar mass of Cobalt is 58.9332g. 58.9332 *3 is 176.7996g.

3 0
3 years ago
Which statement best relates the strength and concentration of a base? At high enough concentrations, a weak base becomes strong
Lorico [155]

Answer: Option (b) is the correct answer.

Explanation:

When there are more number of hydroxide ions in a solution then there will be high concentration of OH^{-} or hydroxide ions. As a result, more will be the strength of base in that particular solution.

A base is strong when it readily dissociate into its ions in the solution. When a base is strong, then it does not matter at what concentration it is dissolved in the solution because despite of its low concentration it will remain a strong base.

Thus, we can conclude that out of the given options, the statement even at low concentrations, a strong base is strong best relates the strength and concentration of a base.


6 0
3 years ago
Read 2 more answers
How many moles of methane are in 20.32 x 10^16 molecules
Marizza181 [45]

Taking into account the definition of avogadro's number, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

First of all, you have to know that Avogadro's number indicates the number of particles of a substance (usually atoms or molecules) that are in a mole.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of methane, then 20.32×10¹⁶ molecules are contained in how many moles of methane?

amount of moles of methane= (20.32×10¹⁶ molecules × 1 mole)÷ 6.023×10²³ atoms

Solving:

<u><em>amount of moles of methane= 3.37×10⁻⁷ moles</em></u>

Finally, 3.37×10⁻⁷ moles of methane are 20.32×10¹⁶ molecules.

Learn more about Avogadro's Number:

  • <u>brainly.com/question/11907018?referrer=searchResults </u>
  • <u>brainly.com/question/1445383?referrer=searchResults </u>
  • <u>brainly.com/question/1528951?referrer=searchResults</u>
7 0
2 years ago
How many atoms are there in 2.0 moles of magnesium (Mg)?
hjlf

Answer:

It should be 1. 1.2 X 10^24

Explanation:

7 0
2 years ago
A) Calculate the osmotic pressure difference between seawater and fresh water. For simplicity, assume thatall the dissolved salt
never [62]

Answer:

a)  Δπ = 1.264 atm

b) W = 128 joules

c)  ΔH >> W  ( a factor greater than 17,000 )

Explanation:

a) The osmotic pressure, π , is determined by :

π = nRT/V, where n= moles of solute

                          R= 0.0821 Latm/kmol

                          T = 300 K

calling π(sw) osmotic pressure for  for sea water and π (fw) for fresh water,

salinity of sea water = 3.5 g / 1L water   (assuming only NaCl for the salts)

salinity of fresh water = 0.5 parts per thousand (range: 0- 0.5 ppt)

πsw = (3.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 1.475 atm

πfw = (0.5 g/58.44 g/mol) (0.0821 Latm/Kmol) (300 K ) /1 L = 0.211 atm

d water = 1 g/cm³

Δ π = (1.475 - 0.211) = 1.264 atm

b) W = Δπ V = 1.426 atm x 1L = 1.43 L-atm

1 L-atm = 101.33 j

W =  101.33 j/ Latm x  1.43 Latm = 128 joules

c) ΔH = Q₁ + nΔH vap, where

            Q₁  = heat required to bring the solution from 300 K to boiling, 373 K

            ΔH vap = heat of vaporization

Q = mCΔT = 1000 g x 4.186 j x 73 K = 305.6 j = 0.3056 kj

ΔH vap = (1000 g/ 18 g/mol ) 40.7 kj/mol = 2,261 kj

ΔH =  0.3056 kj + 2,261 kj = 2,261.3 kj

Note = Q << ΔH vap and we could have neglected it.

This result shows why nobody talks about evaporation of sea water to produce fresh water ΔH >> W

6 0
3 years ago
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