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9966 [12]
3 years ago
8

65.39Atomic # =Atomic Mass =# of Protons =# of Neutrons =# of Electrons =​

Chemistry
1 answer:
ratelena [41]3 years ago
8 0

Answer:

The answer to your question is below

Explanation:

Atomic mass = 65.39 g

Searching this number in the periodic table we find that the element is Zinc.

Then:

# of Protons = 30

# of neutrons = atomic mass - # of protons

                       = 65.39 - 30

                        = 35.39

# of electrons = # of protons = 30

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The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be
Stels [109]

Explanation:

1) Initial mass of the Cesium-137=N_o= 180 mg

Mass of Cesium after time t = N

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

Half life of the cesium-137 = t_{1/2}=30 years[p/tex]where,
[tex]N_o = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

t_{\frac{1}{2}} = half life of the isotope

\lambda = rate constant

N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

N=180mg\times e^{-\frac{0.693}{30 years}\times t}

Mass that remains after t years.

N=180 mg\times e^{0.0231 year^{-1}\times t}

Therefore, the parent isotope remain after one half life will be, 100 grams.

2)

t = 70 years

N_o=180 mg

t_{1/2}= 30 yeras

N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

3)

N_o=180 mg

t_{1/2}= 30 yeras

N = 1 mg

t = ?

1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}

\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0
3 years ago
Someone help please I don’t know the answer to the question I meeed help
mihalych1998 [28]

Answer: 143.3  

137+115+104+263+98 divided by 5.Which gives us 143.3

5 0
3 years ago
Vapor pressure can be described as: A) the temperature at which bubbles of vapor appear in a liquid. B) the pressure exerted on
Vanyuwa [196]

Answer: Option (D) is the correct answer.

Explanation:

Vapor pressure is defined as the pressure exerted by the vapors which are present on the surface of a liquid.

For example, vapor pressure of water at room temperature is 0.0313 atm.

On the other hand, the temperature at which the vapor pressure of a liquid equals atmospheric pressure is known as boiling point.

For example, boiling point of water at room temperature is 100^{o}C.

Thus, we can conclude that vapor pressure can be described as the pressure exerted by a gas above the surface of its liquid.

4 0
3 years ago
What's the molar mass of Li3p
spayn [35]

Answer:

51.79g Li₃P.

Explanation:

Li has a molar mass of 6.94 g (since there are 3, you multiply it 3 times) and P has a molar mass of 30.97 g. 6.94(3) + 30.97 = 51.79g.

4 0
3 years ago
Use the drop-down menus to select the names of the labeled structures.<br><br> A: B: C:
Naya [18.7K]

Answer:

A Petal B Stigma C Stamen

Explanation:

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