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3 years ago

Calculate how many valence electrons are in H2CO, N2, Cl2?

Chemistry

2 answers:

netineya [11]3 years ago

8 0

In H2CO, C is bonded to H, H and O. Write down the valence electrons of each element.2 H = 1x 2 = 2.C= 4O = 6Total: 12

Ket [755]3 years ago

6 0

In H2CO, C is bonded to H, H and O. Write down the valence electrons of each element. 2 H = 1x 2 = 2. C= 4 O = 6 Total 12

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A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation

qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its wavelength and temperature is given by Wien's displacement law.

$\lambda_{max}=\frac{b}{T}$

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

$T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K }{0.21m} =0.014K$

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3 years ago

How do you solve this

3241004551 [841]

With your mind. Boom. Lol I'm sorry I don't know I just need points

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2 years ago

An organic fertiliser in which plants are ploughed back into the soil

Evgen [1.6K]

Answer:

It was called MANURE

Explanation:

Its a type of fertilizer which plant are ploughed back into the soil.

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2 years ago

In right triangle EFG, mE = 25. In right triangle HJK, mH = 25. Which similarity postulate or theorem proves that EFG and HJK ar

Rus_ich [418]

The angle- angle similarity postulate. It states that if a triangle has two equal corresponding angles the angles are similar.

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3 years ago

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Suppose a mercury thermometer contains 3.250g of mercury and has a capillary that is 0.180mm in diameter.. How far does the merc

Helga [31]

1) You need to get volume of both temperatures by using first attached formula V= Mass/Density $V_1 = (3.250 g)/(13.596 g/(cm^3)) = .2390 cm^3
At 25 degrees C (V_2e have:

V_2 = (3.250 g)/(13.534 g/(cm^3)) = .2401 cm^3$

2) Using the second formula you get the height of 0 degree
$h = V/(pi * r^2)


h_1 =(.2390 cm^3)/(pi*(.009 cm)^2) = 939.2 cm$

(radius in cm is $(0.180 mm) / 2 * (1 cm)/(10 mm) or .009 cm$

3) Then with h1 you can easily get the height of 25 degrees
$h_2 =(.2401 cm^3)/(pi*(.009 cm)^2) = 943.5 cm$

Subtract 943.5 cm - 939.2 cm, and obtain a rise in mercury height of 4.3 cm

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2 years ago

Read 2 more answers