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Andre45 [30]
3 years ago
8

An elementary school art class teacher plans to display artwork next to the door of each of the classrooms in the school. Each c

lassroom door will only have one piece of artwork displayed, and the school has 22 such doors. If the teacher has 12 sketches and 16 oil paintings, what is the probability that 10 sketches and 12 oil paintings are chosen to be displayed?
Mathematics
1 answer:
QveST [7]3 years ago
5 0

Answer: Our required probability is 0.32.

Step-by-step explanation:

Since we have given that

Number of doors to be selected in a manner  = 22

Number of sketches = 12

Number of oil paintings = 16

Total number of doors we have =12+16 =28

We need to find the probability that 10 sketches and 12 oil paintings are chosen to be displayed.

So, probability would be

\dfrac{^{12}C_{10}\times ^{16}C_{12}}{^{28}C_{22}}\\\\=\dfrac{66\times 1820}{376740}\\\\=\dfrac{120120}{376740}\\\\=0.3188\\\\\approx 0.32

Hence, our required probability is 0.32.

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Read 2 more answers
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GREYUIT [131]
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
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each have two twos. both have one 5, so we know our answer will look something like
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now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
{2}^{2}  \times {3}^{2}  \times 5 \times stuff

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how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
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