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Andre45 [30]
3 years ago
8

An elementary school art class teacher plans to display artwork next to the door of each of the classrooms in the school. Each c

lassroom door will only have one piece of artwork displayed, and the school has 22 such doors. If the teacher has 12 sketches and 16 oil paintings, what is the probability that 10 sketches and 12 oil paintings are chosen to be displayed?
Mathematics
1 answer:
QveST [7]3 years ago
5 0

Answer: Our required probability is 0.32.

Step-by-step explanation:

Since we have given that

Number of doors to be selected in a manner  = 22

Number of sketches = 12

Number of oil paintings = 16

Total number of doors we have =12+16 =28

We need to find the probability that 10 sketches and 12 oil paintings are chosen to be displayed.

So, probability would be

\dfrac{^{12}C_{10}\times ^{16}C_{12}}{^{28}C_{22}}\\\\=\dfrac{66\times 1820}{376740}\\\\=\dfrac{120120}{376740}\\\\=0.3188\\\\\approx 0.32

Hence, our required probability is 0.32.

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Step-by-step explanation:

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2 1/2 * 3/4 =

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1 7/8 cups of butter <====

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3 years ago
Which number is closest to √18
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Answer:

4.2 or 4

Step-by-step explanation:

√18 = 4.24264068712

or 4.2

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Solve the Quadratic equation
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Wich graph matches the equation y+3=2(x+3)
never [62]

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The leftmost graph [with the points (-3,-3) and (0,3)]

Step-by-step explanation:

y+3=2(x+3)

y+3=2x+6

y=2x+3

The y-intercept is 3, meaning that the line passes through the point (0,3), and it's slope is 2, so it travels 2 units up and 1 unit over. Thus the correct graph is the top left graph, with the two points (-3,-3) and (0,3).

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7 0
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At the Denver zoo, adult admission is $15 and children's is $9 a group of 12 people go to the zoo. Their total admission was $15
Natasha2012 [34]

Answer:

The number of adults admitted at the zoo=7

The number of children admitted at the zoo=5

Step-by-step explanation:

a). Determine first expression

Let the number of each group be as follows;

adults=a

children=c

total number of people=12

This can be expressed as;

number of people=number of children+number of adults

replacing;

a+c=12...equation 1

b). Determine the second expression

Let the total cost be expressed as shown;

total cost=(cost per child×number of children)+(cost per adult×number of adults)

where;

total cost=$150

cost per child=$9

number of children=c

cost per adult=$15

number of adults=a

replacing;

(15×a)+(9×c)=150

15 a+9 c=150...equation 2

c). Combine equation 1 and 2 and solve simultaneously

1(15 a+9 c=150)

-

9(a+c=12)=9 a+9 c=108

(15 a-9 a)+(9 c-9 c)=(150=108)

6 a=42

a=42/6

a=7

replacing the value for a in equation 1

7+c=12

c=12-7=5

The number of adults admitted at the zoo=7

The number of children admitted at the zoo=5

3 0
4 years ago
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