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2 years ago

Ill give brain if you answer

Mathematics

2 answers:

nordsb [41]2 years ago

8 0

Answer:

3/2x

Step-by-step explanation:

the answer is 3/2x

Lina20 [59]2 years ago

3 0

Answer:

3/2x is your final answer .

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Find the degree of the polynomial: a^3+3a^2−5a

emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

$a^3+3a^2-5a$

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

$a^3+3a^2- 5a$

The terms are

$a^3$

$3a^2$

$5a$

The term $a^3$ has the largest exponent of 3

Note: The degree of the polynomial does not depend on coefficients of the terms

3 0

3 years ago

Select the correct answer from each drop-down menu.

Ahat [919]

Answer:

Cos θ = -4/5

Tan θ = -3/4

Step-by-step explanation:

The question is as following:

Select the correct answer from each drop-down menu.

Angle θ lies in the second quadrant, and sin θ =3/5.

cos θ = -4/5, -3/5, 3/5, 4/5

tan θ = -4/3, -3/4, 3/4, 4/3

==================================================

Since, the angle lies in second quadrant (negative x axis and positive y axis) we can deduce that cos θ is negative and tan θ is also negative.

If sin θ =3/5

$cos \ \theta =\sqrt{1-sin^2 \theta} = \sqrt{1-(\frac{3}{5} )^2} =\sqrt{1-\frac{9}{25} }=\sqrt{\frac{16}{25} } =\frac{4}{5}$

∴ Cos θ = -4/5 ⇒ because θ lies in the second quadrant.

And

Tan θ = (sin θ)/(cos θ) = (3/5) / (-4/5) = -3/4.

3 0

3 years ago

Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)

Likurg_2 [28]

Answer:

$d = 14$

$(-2,-1)$

General Formulas and Concepts:

Order of Operations: BPEMDAS
Distance Formula: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Step-by-step explanation:

Step 1: Define

(5, -1)

(-9, -1)

Step 2: Find distance d

Substitute: $d = \sqrt{(-9-5)^2+(-1-(-1))^2}$
Simplify: $d = \sqrt{(-9-5)^2+(-1+1)^2}$
Subtract/Add: $d = \sqrt{(-14)^2+(0)^2}$
Evaluate: $d = \sqrt{196}$
Evaluate: $d = \14$

Step 3: Find Midpoint

Substitute: $(\frac{5-9}{2},\frac{-1-1}{2})$
Subtract: $(\frac{-4}{2},\frac{-2}{2})$
Divide: $(-2,-1)$

7 0

2 years ago

Please please!!!! HELP

wlad13 [49]

Answer:

Part A: 38

Part B: 5 or 4 got two different answers

Part C: range because it tells how many numbers are involved apart from the smallest and largest

Step-by-step explanation:

Part A: highest number - lowest number

78-40

Part B

5 0

2 years ago

Which of the following is not always true for a function? A. Each x-value has only one y-value. B. The range is the y-values. C.

nignag [31]

Answer:

Step-by-step explanation:

A is True

B is True

D is true

3 0

2 years ago