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Mamont248 [21]
3 years ago
9

This is due in 2 minutes help!!!..

Chemistry
2 answers:
ololo11 [35]3 years ago
8 0
i think it is A i’m not sure tho
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:A

Explanation: I think I am right

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over a 12.3 minuete period 5.13 E-3 moles of F2 gas effuses from a contaier. How many moles of CH4 gas could effuse from from th
Aleonysh [2.5K]

Answer : The moles of methane gas could be, 7.90\times 10^{-3}mol

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}

[\frac{(\frac{n_1}{t_1})}{(\frac{n_2}{t_2})}]=\sqrt{\frac{M_2}{M_1}}

where,

R_1 = rate of effusion of fluorine gas

R_2 = rate of effusion of methane gas

n_1 = moles of fluorine gas = 5.13\times 10^{-3}mol

n_2 = moles of methane gas = ?

t_1=t_2 = time = 12.3 min  (as per question)

M_1 = molar mass of fluorine gas  = 38 g/mole

M_2 = molar mass of methane gas = 16 g/mole

Now put all the given values in the above formula 1, we get:

[\frac{(\frac{5.13\times 10^{-3}mol}{12.3min})}{(\frac{n_2}{12.3min})}]=\sqrt{\frac{16g/mole}{38g/mole}}

n_2=7.90\times 10^{-3}mol

Therefore, the moles of methane gas could be, 7.90\times 10^{-3}mol

8 0
3 years ago
Plutonium-240 decays according to the function \[Q(t)=Q _{o}e ^{-kt}\] where Q represents the quantity remaining after t years a
marishachu [46]
To answer the question above, substitute the given values to the given equation,
                                   Q(t) = Q x e^-kt
  
                          12 grams = (36 grams) x e^(-0.00011)(t)

Solving for t gives t = 9,987.38 years or approximately equal to 9,990 years. Thus, the answer is letter C.












4 0
3 years ago
Read 2 more answers
the buret is dirty and drops of NaOH cling to the side walls of the buret as it drained. How does this affect the result for NaO
kykrilka [37]
Since this has to do with titration, the measured volume of NaOH used would be less than the actual volume used because some of the unused NaOH would cling to the sides of the buret and therefore wouldn't factor into the measurement

Hope this helps
6 0
4 years ago
How many grams are in 4.25x10^21 molecules of sodium oxide
Vlada [557]

Answer: 0.37g

Explanation:avogadro number = 6.02214076x10^23 atoms/molecules per mole

a mole of Na2O = 2*23 + 16 = 52 g

4.25x10^21 atoms = 52*(4.25*10^21/6.02214076*10^23) = 0.37 g

7 0
3 years ago
An unknown element X has the following isotopes: 58X (68.00%
wlad13 [49]

The average atomic mass in amu of element X is 58.42 amu

The average atomic mass is the sum of the mass number of each of the isotopes multiplied by their respective abundances.

So;

The average atomic mass of element X is;

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= 39.44 + 15.26 + 3.72

= 58.42 amu

The  average atomic mass in amu of X is 58.42 amu.

Learn more: brainly.com/question/13292428

5 0
3 years ago
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