Strong internolecurar forces (A) hope it helps
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The resulting pressure is 3.093 atm
<u><em>calculation</em></u>
The resulting pressure is calculated using the combined gas equation
That is P₁V₁/T₁ =P₂V₂/T₂ where,
P₁=0.956 atm
V₁=4.95 L
T₁=22.8 c in to kelvin= 22.8 +273 =295.8 k
P₂=? atm
V₂=1.75 L
T₂=65.3 c into kelvin = 65.3 +273 =338.3 K
make P₂ the subject of the formula by multiplying both side of the formula by T₂/V₂
P₂ =T₂P₁V₁ / V₂T₁
P₂ = [(338.3 k x 0.956 atm x 4.95 L) / ( 1.75 L x 295.8 K)] =3.093 atm
(of a reaction or process) accompanied by or requiring the absorption of heat.
Initial temperature = -189.4 °C
<h3>Further explanation</h3>
Given
the volume of a gas is changed from 3.6 L to 15.5 L
final temperature = 87 °C = 87+ 273 = 360 K
Required
initial temperature
Solution
Charles's Law
<em>When the gas pressure is kept constant, the gas volume is proportional to the temperature </em>